 | Samuel Mecutchen, George Mornton Sayre - Arithmetic - 1877 - 200 pages
...will take as many % as 5.11^- is contained times in 30.66§-, which = 6. The rate, therefore, is 6 % . RULE. Divide the given interest by the interest of the given principal for the given time at one per cent. %. At what rate will $180 yield $27 interest in 3 years? 3. At what rate will $600 amount... | |
 | Samuel Mecutchen, George Mornton Sayre - Arithmetic - 1877 - 200 pages
...same rate will take as many years as $30 is contained times in $45, which = 1^. 1^ years = 1 yr. 6 mo. RULE. Divide the given interest by the interest of the given principal at the given rate for one year. 2. I lent a friend $1300, at Q%; at settlement he owed me $1339; how... | |
 | Malcolm MacVicar - Arithmetic - 1878 - 266 pages
...principal for the given time as there are units in the rate ; hence the following 593. RULE.—Divi&e the given interest by the interest of the given principal for the given time at 1 per cent. EXAMPLES FOR PRACTICE. 594. 1. At what rate will $260 gain $45.50 in 2yr. 6 mo.? SOLUTION.—The interest of... | |
 | Benjamin Greenleaf - Arithmetic - 1878 - 468 pages
...; then the required rate will be as many per cent, as 20 is contained times in 120, or 6 per cent. RULE. — Divide the given interest by the interest of the given principal at 1 per cent, for the given time. EXAMPLES. y 2. The interest of $ 144 for 1 year is $ 10.08 ; what... | |
 | Education - 1880 - 956 pages
...instead of "fer cent." f And why did he find the interest on one dollar? He then says, "according to the rule, divide the given interest by the interest of the given principal for the given time at one per cent.", and divides 100 by 16% and says il= 6 per cent. Now it seems to me that ioc-i-.i6%=6oo... | |
 | Samuel Mecutchen - Arithmetic - 1880 - 262 pages
...rate ; or, divide the given amount by the amount of one dollar for the given time and rate. CASE III. Divide the given interest by the interest of the given principal for the given time at one -per cent. CASE IV. Divide the given interest by the interest of the given principal at the given... | |
 | Samuel Mecutchen - Arithmetic - 1880 - 270 pages
...rate ; or, divide the given amount by the amount of one dollar for the given time and rate. CASE III. Divide the given interest by the interest of the given principal for the given time at one per cent. CASE IV. Divide the given interest by the interest of the given principal at the given... | |
 | Silas Sadler Packard, Byron Horton - Business mathematics - 1882 - 324 pages
...$44.10 ( 4£ Ans. Hence the answer is 41 -%. 6)58^ ' $9 32O. RULE. — Divide the given interest bij the interest of the given principal, for the given time, at 1%. NOTE. — When the amount is given, find the interest by subtracting the principal from the amount.... | |
 | Silas Sadler Packard, Byron Horton - Business mathematics - 1882 - 224 pages
...as $25.56 is contained times in $59.427, or 2.325 yr. 2.325 yr. equal 2 yr. 3 mo. 27 da. (201). 323. RULE. — Divide the given interest by the interest of the given principal, at the given rate, for 1 year. The integral part of the quotient will be years. Reduce the decimal,... | |
 | Warren H. Sadler - 1888 - 426 pages
...given interest must proof ._Int. of $630 for 48 da. be 8 fame. 1*. or 8*. at 80 = $6.72. Rule. — Find the interest of the given principal for the given time at 1% per annum ; and divide the resitlt into the given interest. NOTE. — If the amount is given, diminish... | |
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RULE. — Divide the given interest by the interest of the given principal for 1 year, and the quotient is the time. 
