| James Atkins Bullard, Arthur Kiernan - Trigonometry - 1922 - 252 pages
...sine of a middle part is equal to the product of the cosines of the opposite parts. 2. The sine of a **middle part is equal to the product of the tangents of the** adjacent parts. (61) The parts mentioned in the rules are the five so-called circular parts of the... | |
| Science - 1925 - 732 pages
...omitted. The sine of the middle part is equal to the product of the tangents of the adjacent parts. **The sine of the middle part is equal to the product of the** cosines of opposite parts. From these rules the following equations follow: sin a = sin c sm a, tan... | |
| Andrew Wheeler Phillips, Wendell Melville Strong - Trigonometry - 1926 - 332 pages
...: I. The sine of the middle part is equal to the product of the tangents of the adjacent parts. II. **The sine of the middle part is equal to the product of the** cosines of the opposite parts. 84:. In the right spherical triangles considered in this work, each... | |
| Howard Whitley Eves - Mathematics - 1983 - 292 pages
...any middle part is equal to the product of the cosines of the two opposite parts. 2. The sine of any **middle part is equal to the product of the tangents of the two adjacent parts.** (a) By applying each of the above rules to each of the circular parts, obtain the ten formulas used... | |
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