| Science - 1922 - 414 pages
...omitted. The sine of the middle part is equal to the product of the tangents of the adjacent parts. The sine of the middle part is equal to the product of the cosines of opposite parts. From these rules the following equations follow: sin a = sin с sin a, tan... | |
| Smithsonian Institution - Elliptic functions - 1922 - 410 pages
...omitted. The sine of the middle part is equal to the product of the tangents of the adjacent parts. The sine of the middle part is equal to the product of the cosines of opposite parts. From these rules the following equations follow: sin a = sin с sin a, tan... | |
| James Atkins Bullard, Arthur Kiernan - Trigonometry - 1922 - 252 pages
...sine of a middle part is equal to the product of the cosines of the opposite parts. 2. The sine of a middle part is equal to the product of the tangents of the adjacent parts. (61) The parts mentioned in the rules are the five so-called circular parts of the... | |
| Science - 1925 - 726 pages
...omitted. The sine of the middle part is equal to the product of the tangents of the adjacent parts. The sine of the middle part is equal to the product of the cosines of opposite parts. From these rules the following equations follow: sin a = sin c sm a, tan... | |
| Andrew Wheeler Phillips, Wendell Melville Strong - Trigonometry - 1926 - 332 pages
...: I. The sine of the middle part is equal to the product of the tangents of the adjacent parts. II. The sine of the middle part is equal to the product of the cosines of the opposite parts. 84:. In the right spherical triangles considered in this work, each... | |
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