 | Benjamin Greenleaf - Arithmetic - 1861 - 338 pages
...annexed by the figure annexed to the root, and subtract the product from the dividend. To the remainder bring down the next period for a new dividend. Double the root already found for a new divisor, and continue th* operation as before, till all the periods have been... | |
 | Elias Loomis - Algebra - 1862 - 312 pages
...product should be greater than the dividend, diminish the last figure of the root. 5. Double the whole root now found for a new divisor, and continue the...as before, until all the periods are brought down. Ex. 2. Find the square root of 186624. The operation is as follows : 18-66-24 16 432 83 266 249 862... | |
 | John Flint (inspector of schools.) - 1862 - 152 pages
...root and to the divisor. Multiply the divisor thus completed by the figure of the root last found, subtract the product from the dividend, and to the...remainder bring down the next period for a new dividend, and for a new divisor add the figure of the root last found, with which proceed as before, and continue... | |
 | James Bates Thomson - Arithmetic - 1862 - 436 pages
...divisor', multiply the divisor thus completed by the figure last placed in tkt root ; subtract tlte product from the dividend, and to the remainder bring down the next period for a new dividend. IV. Double the root already found for a new partial divisor, divide, &c., as before, and thus continue... | |
 | Charles Davies - Algebra - 1864 - 316 pages
...than the remainder, diminish the last figure of the root by one : V. Double the whole root already found, for a new divisor, and continue the operation...as before, until all the periods are brought down. 132. NOTE.—1. If, after all the periods are brought down, there is no remainder, the given number... | |
 | Charles Davies, William Guy Peck - Mathematics - 1865 - 592 pages
...divisor. IV. Multiply the divisor thus obtained bj the last digit of the root found ; subtract ¡hr product from the dividend, and to the remainder bring down the next period for a new dividend. If the product just found exceeds the dividend, diminish the last c!i^:t of the root found, and proceed... | |
 | George Augustus Walton, Mrs. Electra Nobles Lincoln Walton - Arithmetic - 1865 - 354 pages
...obtained by the last figure of the root, and subtract this product from the dividend ; to the remainder bring down the next period for a new dividend. Double the root figures already found for a new trial divisor, and proceed as before. NOTE I. — When a zero occurs... | |
 | Joseph Ray - Algebra - 1866 - 420 pages
...will be the complete divisor. 4th. Multiply the complete divisor by the last figure of the Tool, and subtract the product from the dividend, and to the...remainder 'bring down the next period for a new dividend, and so proceed until all the periods are brought down. Extract the cube root of the following numbers... | |
 | Joseph Ray - Algebra - 1866 - 252 pages
...and to the remainder bring down the next period for a new dividend. 5. Double the whole root already found for a new divisor, and continue the, operation...as before, until all the periods are brought down. NOTE.—It^ in any case, the dividend will not contain the divisor, the right hand figure of the former... | |
 | Charles Davies - Algebra - 1866 - 314 pages
...than the remainder, diminish the last figure of the root by one : V. Double the whole root already found, for a new divisor, and continue the operation...as before, until all the periods are brought down. 132. NOTE.—1. If, after all the periods are brought down, there is no remainder, the given number... | |
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subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. Double the root now found for a new divisor and continue the operation as before, until all the periods are brought down. EXAMPLES. 1. 
