 | Algebra - 1838 - 372 pages
...was its value ? Ans. £4. 165. 17. To divide the number 90 into four such parts, that if the first be increased by 2, the second diminished by 2, the third multiplied by 2, and the fourth divided by 2, the sum. difference, product, and quotient so obtained, will be all equal to each other. Ans. The parts... | |
 | Charles Davies - Algebra - 1839 - 272 pages
...1+— y+— z=15 ^ to find x, y and z. • o 4 O a;=12, y=20, ^ = 30. 4. Divide the number 90 into four such parts that the first increased by 2, the second...multiplied by 2, and the fourth divided by 2, shall be equal to each other. This question may be easily solved by introducing a new unknown quantity. Let... | |
 | Bewick Bridge - Algebra - 1839 - 280 pages
.../ * o •n -f ~ / j •' DO QUADRATIC EQUATIONS. ' Tf » '.* Qu. 33. Divide the number 90 into four such parts, that the first increased by 2, the second...third multiplied by 2, and the fourth divided by 2, may all be equal to the same quantity. ,,- v : - ., ANSW. 18, 22, 10, 40. ~ft iJ C' s- / f *ff ^ /... | |
 | John D. Williams - Algebra - 1840 - 634 pages
...required. 44. It is required to divide the number 90 into four such parts that if the first part be increased by 2, the second diminished by 2, the third multiplied by 2, and the fourth divided by 2, the sum, difference, product, and quotient shall be all equal. Ans. The parts are 18, 22, 10, and 40.... | |
 | Jeremiah Day - Algebra - 1841 - 354 pages
...of both will be less than that of the first horse by 13 guineas. What is the value of each horse 1 Ans. 56 and 33 guineas. Prob. 30. Divide the number...and z, be three of the parts, the fourth will be 90 - at - y - z. And by the conditions, The parts required are 18, 22, 10, and 40. Prob. 31. Find three... | |
 | Charles Davies - Algebra - 1842 - 284 pages
...3. Given <J la;+ly+l* to find x, y and z. Ans. x=l2, y=20, ^=30. 4. Divide the number 90 into four such parts that the first increased by 2, the second...multiplied by 2, and the fourth divided by 2, shall be equal to each other. This question may be easily solved by introducing a new unknown quantity. Let... | |
 | George Peacock - Algebra - 1842 - 426 pages
...one or more symbols from two or more equations, in the other. (2) To divide the number 108 into four such parts that the first increased by 2, the second...third multiplied by 2, and the fourth divided by 2, may be all equal to each other. Let * be the first, then i + 4 is the second, ^—^- the third, and... | |
 | Charles Davies - Algebra - 1842 - 368 pages
...was its value? Ans. £4. 16s. 17. To divide the number 90 into four such parts, that if the first be increased by 2, the second diminished by 2, the third multiplied by 2, and the fourth divided by 2, the sum, difference, product, and quotient so obtained, will be all equal to each other. Ans. The parts... | |
 | James Bates Thomson - Algebra - 1844 - 272 pages
...will be less than that of the first horse by 13 guineas. What is the value of each horse 1 Prob. 52. Divide the number 90 into 4 such parts, that the first...and z, be three of the parts, the fourth will be 90 — x — y — z. And by the conditions, &c. Prob. 53. Find three numbers, such that the first with... | |
 | Alexander Ingram - 1844 - 262 pages
...separately earn in one day? Ans. A 3s. 8d., B 3s., and C 2s. 4d. 21. To divide 90 into four parts such, that the first increased by 2, the second diminished...2, and the fourth divided by 2, shall all be equal to the same number. Ans. 18, 22, 10, and 40. 22. Find five numbers such, that the first with g the... | |
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Divide the number 90 into 4 such parts, that the first increased by 2, the second diminished by 2, the third multiplied by 2, and the fourth divided by 2, shall all be equal. 
