 | Benjamin Peirce - Algebra - 1864 - 314 pages
...at the right of the divisor. Multiply the divisor, thus augmented, by the last figure of the rootj subtract the product from the dividend, and to the...remainder bring down the next period for a new dividend. Double the root now found for a new divisor and continue the operation as before, until all the periods... | |
 | George Augustus Walton - Arithmetic - 1864 - 376 pages
...square of the last. Multiply this sum by the last term, and subtract the product from the dividend. To the remainder bring down the next period for a new dividend. Multiply the square of the terms of the root already found (considered as fens), by three for a trial... | |
 | George Augustus Walton - Arithmetic - 1864 - 364 pages
...true divisor thus obtained by the last term of the root, and subtract this product from the dividend ; to the remainder bring down the next period for a new dividend. Double the terms of the root already found for a new trial divisor, and proceed as before. NOTE I.... | |
 | Horatio Nelson Robinson - Algebra - 1864 - 444 pages
...to the trial divisor for a complete divisor ; multiply the complete divisor by the trial figure in the root, subtract the product from the dividend, and to the remainder briny down the next period fur a new diuidend. V. Take the last complete divisor, doubling its right-hand... | |
 | Charles Davies - Arithmetic - 1865 - 372 pages
...the root and also annex it to the divisor. IV. Multiply the divisor thus increased, by the last JigKt of the root ; subtract the product from the dividend,...to the remainder bring down the next period for a neic dividend. V. Double the whole root thus found, for a new trial divisor, and continue the operation... | |
 | W H. Wingate - 1865 - 150 pages
...trial divisor and the last figure in the root — add these three results for a subtrahend which take from the dividend, and to the remainder bring down the next period, and proceed as before. EXAMPLE. — Find the cube root of 4.410944. 4.410944(164 1гхЗ=3 Trial Divisor... | |
 | Joseph Ray - Algebra - 1866 - 420 pages
...the figure in the root and also on the right of the divisor. 4th. Multiply the divisor thus increased by the last figure of the root; subtract the product...remainder bring down the next period for a new dividend. 5th. Double the whole root already found for a new divisor, and continue the operation as before, until... | |
 | Joseph Ray - Algebra - 1866 - 250 pages
...figure in the root, and also on the right of the divisor. 4. Multiply the divisor, thus increased, by the last figure of the root; subtract the product...remainder bring down the next period for a new dividend. 5. Double the whole root already found for a new divisor, and continue the operation as before, until... | |
 | Horatio Nelson Robinson - Algebra - 1866 - 328 pages
...divisor; add the correction, and the result will be the complete divisor. V. Multiply the complete divisor by the last figure of the root, subtract the product...from the dividend, and to the remainder bring down another period for a new dividend. VI. Add together the square of the last figure of the root, the... | |
 | Joseph Ray - Algebra - 1852 - 422 pages
...will be the complete divisor. 4th. Multiply the complete divisor by the last figure of the root, and subtract the product from the dividend, and to the...remainder bring down the next period for a new dividend, and so proceed until all the periods are brought down. Extract the cube root of the following numbers.... | |
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Multiply the divisor, thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 
