 | Robert Simson - Trigonometry - 1835 - 544 pages
...equal to KCF, and the right angle FHC equal to the right angle FKC; in the triangles FHC, FKC there are two angles of the one equal to two angles of the other, and the side FC, which is opposite to one of the equal angles in each, is common to both : therefore... | |
 | Mathematics - 1836 - 488 pages
...which has the greater base, shall be greater than the angle contained by the sides of the other. XXVI. If two triangles have two angles of the one equal to two angles of the other, each to each ; and one side equal to one side, viz. either the sides adjacent to the equal angles, or the sides opposite... | |
 | John Playfair - Geometry - 1836 - 148 pages
...bisected by BD, and that the right angle BED is equal to the right angle BFD, the two Iriangles EBD, FBD have two angles of the one equal to two angles of the other, and the side BD, which is opposite to one of the equal angles in each, is common to both ; therefore... | |
 | William Whewell - 1837 - 226 pages
...angle; therefore MLN is equal to LKH; and the angles at H and at N are right angles. Therefore the triangles have two angles of the one equal to two angles of the other ; and the side KL is equal to LM. Therefore the triangles are equal, and HL is equal to MN; that is,... | |
 | Andrew Bell - Euclid's Elements - 1837 - 290 pages
...by BD ; and because the right angle BED is equal to the right angle BFD, the two triangles EBD, FBD, have two angles of the one equal to two angles of the other ; and the side BD, which is opposite to one of the equal angles in each, is common to both ; therefore... | |
 | Euclid, James Thomson - Geometry - 1837 - 410 pages
...is equal (const.) to FBD, and that the right angles BED, BFD are equal, the two triangles EBD, FBD have two angles of the one equal to two angles of the other, and the side BD, which is opposite to one of the equal angles in each, is common to both ; therefore... | |
 | A. Bell - Conic sections - 1837 - 180 pages
...Def. 7)i and therefore the angles AFG, AEG, are also equal. The triangles AGE, AGF, have therefore two angles of the one equal to two angles of the other, and they have also the side AG common ; wherefore they are equal, and the side AF is equal to the side... | |
 | Euclides - Euclid's Elements - 1837 - 112 pages
...be > Z EOF. PROPOSITION XXVI. (Argument ad absurdum). Theorem. If two triangles have two angles of one equal to two angles of the other, each to each, and one side equal to one side; viz., either the sides adjacent to the equal angles, or opposite to the... | |
 | Euclides - 1838 - 264 pages
...ij greater than the angle EDF. Wherefore, if two triangles, &c. Q. t, n. PROP. XXVI. THEOR. °V'.' If two triangles have two angles of the one equal to two angles of the other, each to each ; and one side equal to one side, vis. either the sides adjacent to the equal angles, or the sides opposite... | |
 | Robert Simson - Geometry - 1838 - 434 pages
...bisected by BD, and that the right angle BED is equal to the right angle BFD, the two triangles EBD, FBD have two angles of the one equal to two angles of the other, and the side BD, which is opposite to one of the equal angles in each is common to both ; therefore... | |
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If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz. 
