 | George Albert Wentworth - Algebra - 1895 - 376 pages
...eliminate by comparison, therefore, From each equation obtain the value of one of the unknown numbers in terms of the other. Form an equation from these equal values and reduce the Exercise 60. Solve by comparison : 1. x+ y = 30 1 9. 2x- 3y = I| Bx- 2 = 25j 2. 7x+ 3y=70| 10. 50a;-... | |
 | William Freeland - Algebra - 1895 - 328 pages
...... y = l. Substitute in (1), x + 3 = 27. .-. ж = 13. 182. Hence, to eliminate by comparison : Find the value of one of the unknown quantities in terms of the other in each equation ; make a new equation from the equal vulues thus obtained. From this new equation... | |
 | Fletcher Durell, Edward Rutledge Robbins - Algebra - 1897 - 482 pages
...13 Substitute for у in (3), x = 36 ~ 26 = 2 о Hence, in general, Jn one о/ ¿Ле given equations obtain the value of one of the unknown quantities in terms of the other unknown quantity ; Substitute this value in the other equation and solve. EXERCISE 56. Solve by substitution.... | |
 | Webster Wells - Algebra - 1897 - 426 pages
...- 45х + 153 = 120. Иг = -33, Whence, • х = — 3. RULE. From one of the given equations find the value of one of the unknown quantities in terms of the other, and substitute t7гis value in place of that quantity in the other equation. EXAMPLES. Solve by the... | |
 | Webster Wells - Algebra - 1897 - 422 pages
...Substitutine the value of r, in ж = -3. (*. „ -15-17 1 EULE. From one of the given equations find the value of one of the unknown quantities in terms of the other, and substitute this value in place of that quantity in the other equation. EXAMPLES. Solve by the method... | |
 | Webster Wells - Algebra - 1897 - 386 pages
...m. „ -15-17 -4. firiViatitnfiTinr t.ha valiip nf v. in RULE. From one of the given equations find the value of one of the unknown quantities in terms of the other, and substitute this value in place of that quantity in the other equation. EXAMPLES. Solve by the method... | |
 | Electrical engineering - 1897 - 672 pages
..._1+2X4 ~~3 ; whence, .* = 3. Ans. 61O. To Eliminate by Comparison : Rule. — From cadi equation find the value of one of the unknown quantities in terms of the oilier. Form a new equation by placing tliese two values equal to each other and solve. Elimination... | |
 | International Correspondence Schools - Civil engineering - 1899 - 722 pages
...quantities will be considered. 609. To Eliminate by Substitution : Rule. — From one equation, find t/ie value of one of the unknown quantities in terms of the other. Substitute this value for the same unknown quantity in tlie other equation. EXAMPLE. — Solve the... | |
 | William Kent - Engineering - 1902 - 1204 pages
...= 24 - 90 -f 140 = 14, whence y = - 2. Substitute this value in (1): 2x - 6 = 8; x = 7. Elimination by comparison. — From each equation obtain the value...Form an equation from these equal values, and reduce this equation. 2* — 90=11. (1). From (1) we find x = — -„Solve I \Sx — 40 = 7. (2). From (2)... | |
 | William Kent - Engineering - 1907 - 1206 pages
...- 9y + Uij = 14, whence y = — 2. Substitute this value in (1): 2:e — 6 = 8; x = 7. Elimination by comparison.— From each equation obtain the value of one of the unknown quantities in ternis of the other. Form an equation from these equal values, and reduce this equation. {2x - 9y =... | |
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Find the value of one of the unknown quantities, in terms of the other and known quantities... 
