 | Frank Robertson Van Horn - Crystallography - 1903 - 704 pages
...triangles which may be inscribed in the ground-form and solved by Napier's rules, which are as follows: the sine of the middle part equals the product of the tangents of the adjacent parts; the sine of the middle part equals the product of the cosines of the opposite parts. In the figure... | |
 | Claude Irwin Palmer, Charles Wilbur Leigh - Logarithms - 1916 - 348 pages
...co-c and co-ß are the opposite parts. Napier's rules are then stated as follows: (1) The sine of a middle part equals the product of the tangents of the adjacent parts. (2) The sine of a middle part equals the product of the cosines of the opposite parts. It may assist... | |
 | John William Norie, J. W. Saul - Nautical astronomy - 1917 - 642 pages
...said that ZA is the middle part and the sides b and c the adjacent parts. Napier's first rule says the sine of the middle part equals the product of the tangents of the adjacent parts. That is — Sine A = tan. bx tan. c bat as the complements of A and side 6 are to be taken the formula... | |
 | Frank Moore Colby, Talcott Williams - Education - 1922 - 922 pages
...• and two opposite parts, as co-A, c. The rules of Napier connect these by the following mnemonic: The sine of the middle part equals the product of the tangents of the adjacent parts, and the sine of the middle part equals the product of the cosines of the opposite parts. CnPCULAT'ING... | |
 | Pauline Sperry - Spherical trigonometry - 1928 - 88 pages
...adjacent parts, and the remaining parts are the opposite parts. The rules follow. RULE 1. The sine of a middle part equals the product of the tangents of the adjacent parts. RULE 2. The sine of a middle part equals the product of the cosines of the opposite parts. Since any... | |
 | David Adamy - Electronics in military engineering - 252 pages
...changed to the cofunction in Napier's rules (eg, sine becomes cosine). Napier's rules are as follows: • The sine of the middle part equals the product of the tangents of the adjacent parts. (Remember the "co-"s.) • The sine of the middle part equals the product of the cosines of the opposite... | |
 | United States. War Department - 190 pages
...it, adjacent parts, and the remaining two, opposite parts. Napier's rules state: (1 ) The sine of a middle part equals the product of the tangents of the adjacent parts. Thus: sin 6=tan a-tan (90°— A) hut tan (90°— A)=cot4 (by definition) therefore sin 6 = tan a-cot... | |
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I. The sine of the middle part is equal to the product of the tangents of the adjacent parts. II. The sine of the middle part is equal to the product of the cosines of the opposite parts. 
