 | Evan Wilhelm Evans - Geometry - 1884 - 242 pages
...of the circle. Apply Ex. 11, and prove BH + AN = AB. CN and CH are each equal to radius (?). M 35. If from any point in the base of an isosceles triangle parallels to the sides are drawn, a parallelogram is formed whose perimeter is equal to the sum of the equal sides of the triangle. 36.... | |
 | Webster Wells - Geometry - 1886 - 392 pages
...the exterior angle at the vertex of a triangle is parallel to the base, the triangle is isosceles. 3. If from any point in the base of an isosceles triangle parallels to the equal sides are drawn, the perimeter of the parallelogram thus formed is equal to the sum of the equal... | |
 | William Chauvenet, William Elwood Byerly - Geometry - 1887 - 331 pages
...to the vertical angle of an isosceles triangle ABC is parallel to the base BG. 2. If from a variable point in the base of an isosceles triangle parallels to the sides are drawn, a parallelogram is formed whose perimeter is constant. 3. The sum of the four lines drawn to the vertices... | |
 | George Albert Wentworth - Geometry - 1888 - 272 pages
...B double the angle A. If BD bisect the angle B, and meet AC in D, show that BD is equal to AD. 54. If from any point in the base of an isosceles triangle parallels to the legs are drawn, show that a parallelogram is formed whose perimeter is constant, and equal to the sum... | |
 | George Albert Wentworth - 1889 - 264 pages
...joined to the extremity of the base, the joining line is perpendicular to the base. 16. If through any point in the base of an isosceles triangle parallels to the legs are drawn, a parallelogram will be formed, having its perimeter equal to the sum of the legs of... | |
 | George Albert Wentworth - 1889 - 276 pages
...joined to the extremity of the base, the joining line is perpendicular to the base. 16. If through any point in the base of an isosceles triangle parallels to the legs are drawn, a parallelogram will be formed, having its perimeter equal to the sum of the legs of... | |
 | Seth Thayer Stewart - Geometry - 1891 - 426 pages
...adjacent to one base of a trapezoid are equal, those adjacent to the other base are also equal. 5. If from any point in the base of an isosceles triangle parallels to the equal sides are drawn, the perimeter of the parallelogram thus formed is equal to the sum of the equal... | |
 | William Chauvenet - 1893 - 340 pages
...to the vertical angle of an isosceles triangle ABC la parallel to the base BO. 8, If from a variable point in the base of an isosceles triangle parallels to the sides are drawn, a parallelogram is formed whose perimeter is constant. P o 3. The sum of the four lines drawn to the... | |
 | Seth Thayer Stewart - Geometry - 1893 - 262 pages
...i., P. xvII.) ; also, Z2+Z3 = 2Ls; Z / + ¿4= Z 2 + ¿3 (Ax. i.); but, ¿1 = ¿2; .-., Z 4= ¿ 3. 5. If from any point in the base of an isosceles triangle parallels to the equal sides are drawn, the perimeter of the parallelogram thus formed is equal to the sum of the equal... | |
 | Andrew Wheeler Phillips, Irving Fisher - Geometry, Modern - 1896 - 276 pages
...sides, but greater than half their sum. Hint.— Apply §§ 7 and 95. 139. Exercise. — If from a point in the base of an isosceles triangle parallels to the sides are drawn, a parallelogram is formed, the sum of whose four sides is the same wherever .the point is situated... | |
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If from any point in the base of an isosceles triangle parallels to the equal sides be drawn, show that a parallelogram is formed whose perimeter is equal to the sum of the equal sides of the triangle. 
