 | Daniel W. Fish - Arithmetic - 1883 - 348 pages
...6OO ft., area. 2. Find the area of a triangle whose base is 20 ft. and each, of the other sides 15 ft RULE. — From half the sum of the three sides subtract each side separately ; multiply the half -sum and the three remainders together ; the square root of the product... | |
 | Daniel W. Fish - Arithmetic - 1883 - 364 pages
...COO ft., area. 2. Find the area of a triangle whose base is 20 ft. and each of the other sides 15 ft. RULE. — From half the sum of the three sides subtract each side separately j multiply the half-sum and the three remainders together; the square root of the product... | |
 | Euclides - 1884 - 434 pages
...into the form of a rule, thus : From half the sum of the three sides, subtract each side separately ; multiply the half sum and the three remainders together, and the square root of the product will be the area.* 1. If from B there be drawn BE j_ AC or AC produced, then BC . CD =... | |
 | Colin Arrott R. Browning - 1884 - 274 pages
...heightTT . , - 2 area He'Sht = T5T(15) When we know the length of each side, but not the perpendicular. Rule : — From half the sum of the three sides subtract each side separately ; multiply the half sum and the three remainders continually together, and the square root... | |
 | George Bruce Halsted - Geometry - 1885 - 389 pages
...vertex, to find the area of a triangle. 319 808. Given, the three sides, to find the area of a triangle. RULE. From half the sum of the three sides subtract each side separately ; multiply together the half -sum and the three remainders. The square root of this product... | |
 | George Bruce Halsted - Geometry - 1886 - 394 pages
...vertex, to find the area of a triangle. 319 808. Given, the three sides, to find the area of a triangle. RULE. From half the sum of the three sides subtract each side separately ; mult1ply together the half-sum and the three remainders. The square root of tltis product... | |
 | Christian Brothers - Arithmetic - 1888 - 484 pages
...— 25 = 2? 52 — 39 = 13 52 — 40 = 12 52 x 27 x 13 x 12 = 219024 Area = -v/219024 = 468 sq. yd. RULE. — From half the sum of the three sides, subtract each side separately ; then multiply the half sum and the three remainders together; and the square root of the... | |
 | James William Nicholson - Arithmetic - 1889 - 408 pages
...15. 15 — 5 = 10, 15 — 12 = 3, 15 — 13 = 2. 15 X 10 X 3 X 2 = 900; v'itOO = 30, Ans. in sq. in. RULE. — From half the sum of the three sides subtract each side; then multiply the half sum and the three remainders together , and extract the square root of the product.... | |
 | Thomas Baker - Railroads - 1891 - 262 pages
...has been made, and the work must be repeated. TO FIND THE AREA OF A TRIANGLE FROM THE THREE SIDES. RULE. From half the sum of the three sides subtract each side severally and reserve the three remainders ; multiply the half sum continually by the three remainders, and the... | |
 | John Groesbeck - 1891 - 426 pages
...per square foot. Ans. 63 cents. 447. To find the Area of a Triangle when the Three Sides are given. Rule. — From half the sum of the three sides subtract each side separately. Multiply the half sum and the three remainders together, and extract the square root of... | |
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From half the sum of the three sides, subtract each side severally; multiply the half sum, and the three remainders together, and the square root of the product will be the area required. Example. — Required the area of a triangle, whose sides are 50,... 
