 | Euclides - 1864 - 262 pages
...ABC is the isosceles triangle. 65. This construction may be effected by means of Prob. 4, p. 71. 66. The perpendicular from the vertex on the base of an equilateral triangle bisects the angle at the vertex which is two-thirds of one right angle. 67. Let ABC be the equilateral... | |
 | Euclides - 1864 - 448 pages
...ABC is the isosceles triangle. 65. This construction may be effected by means of Prob. 4, p. 71. 66. The perpendicular from the vertex on the base of an equilateral triangle bisects the angle at the vertex, which is two-thirds of one right angle. 67. Let ABC be the equilateral... | |
 | Robert Potts - 1865 - 528 pages
...perpendiculars on the same side of the diameter will be equal to the perpendicular on the other side. 10. The perpendicular from the vertex on the base of an...inscribed in a circle whose diameter is the base. Required proof. 11. If an equilateral triangle be inscribed in a circle, and the adjacent arcs cut... | |
 | Richard Wormell - Geometry, Modern - 1868 - 286 pages
...the line meets the circumference, according as the line does or does not cut the base. 4. Prove that the perpendicular from the vertex on the base of an...inscribed in a circle whose diameter is the base. 5. If an equilateral triangle be inscribed in a circle, and the adjacent arcs cut off by two of its... | |
 | Robert Potts - 1868 - 434 pages
...ABC is the isosceles triangle. 65. This construction may be effected by means of Prob. 4, p. 71. 66. The perpendicular from the vertex on the base of an equilateral triangle bisects the angle at the vertex, -which is two-thirds of one right angle. 67. Let ABC be the equilateral... | |
 | Dublin city, univ - 1869 - 336 pages
...(a + c) ac > 6abc. 12. Solve the equations ia 4 ?ii i xt- 4«T V> X^M = cf 4s a1 c. DR. STUBBS. 1. The perpendicular from the vertex on the base of an equilateral triangle ABC is produced to a point below the base, equally distant from the base with the vertex ; through... | |
 | Richard Wormell - Geometry, Plane - 1870 - 304 pages
...the line meets the circumference, according as the line does or does not cut the base. 4. Prove that the perpendicular from the vertex on the base of an...inscribed in a circle whose diameter is the base. 5. If an equilateral triangle be inscribed in a circle, and the adjacent arcs cut off by two of its... | |
 | Robert Potts - Geometry - 1876 - 446 pages
...ABC is the isosceles triangle. 65 This construction may be effected by means of Prob. 4, p. 71. 66. The perpendicular from the vertex on the base of an equilateral triangle bisects the angle at the vertex, which is two-thirds of one right angle. 67. Let ABC be the equilateral... | |
 | Education, Higher - 1881 - 504 pages
...Books IV. and VI. 12. Describe a circle passing through three points not in the same straight line. 13. The perpendicular from the vertex on the base of an...inscribed in a circle whose diameter is the base. 14. If the sides of two triangles, about each of their angles, be proportionals, the triangles shall... | |
 | Euclides - 1884 - 434 pages
...and the given circle. 3. The perpendicular from the vertex to the base of an equilateral triangle = the side of an equilateral triangle inscribed in a circle whose diameter is the base. 4. The area of an inscribed regular hexagon = three.fourths of the area of the regular hexagon circumscribed... | |
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The perpendicular from the vertex on the base of an equilateral triangle is equal to the side of an equilateral triangle inscribed in a circle, whose diameter is the base. 
