 The coefficient of any term may be found by multiplying the coefficient of the preceding term by the exponent of a in that term, and dividing this product by the number of the term.  Algebra for Colleges and Schools - Page 166by Henry Sinclair Hall, Samuel Ratcliffe Knight - 1897 - 516 pagesFull view - About this book
 | Herbert Ellsworth Slaught, Nels Johann Lennes - Algebra - 1916 - 280 pages
...binomial ; and the coefficient of any other term may be found by multiplying the coefficient of the next preceding term by the exponent of a in that term and dividing this product by a number one greater than the exponent of 6 in that term. 5. The coefficients of any... | |
 | Ernst Rudolph Breslich - Logarithms - 1917 - 408 pages
...determined by means of the coefficient of the term just preceding, according to the following rule: Multiply the coefficient of the preceding term by the exponent of a in that term and divide the product by the number of that term. Thus in (a+6)6 the coefficient of the fifth term is... | |
 | Herbert Ellsworth Slaught, Nels Johann Lennes - Algebra - 1917 - 674 pages
...of the second term is the same as the index of the power. The coefficient of each succeeding term is found by multiplying the coefficient of the preceding term by the exponent of the first letter in that term and dividing by the exponent of the second letter increased by one. »Articles... | |
 | Henry Sinclair Hall - 1918 - 382 pages
...coefficient of the first term is Í. (5) The coefficient of the second term is the same as the indeж of the binomial. (6) The coefficient of any term may...multiplying the coefficient of the preceding term by the eжponent of a in that term, and dividing the result by the eжponent of b plus 1. Er. 1. Expand (a... | |
 | Joseph Victor Collins - Algebra - 1918 - 360 pages
...the exponent of (a — A) in the left member ; also that each succeeding coefficient can be obtained by multiplying the coefficient of the preceding term by the exponent of the leading letter a, and dividing the product by the exponent of the other letter increased by 1.... | |
 | Fletcher Durell, Elmer Ellsworth Arnold - Algebra - 1920 - 416 pages
...coefficient of the second term is the index of the required power. In each succeeding term the coefficient is found by multiplying the coefficient of the preceding...term by the exponent of a in that term, and dividing by the number of the preceding term. IV. Signs of terms. If the binomial is a difference, the signs... | |
 | Julius Lederer Neufeld - Algebra - 1920 - 412 pages
...the coefficients in the same form as that given in the formula. It is evident that any coefficient may be found by multiplying the coefficient of the preceding term by the exponent of a and dividing by 1 more than the exponent of b. 1. Expand (a + 6)6. (a + 6)6 = a6 + 6a*6 + — X-5 aW... | |
 | Fletcher Durell, Elmer Ellsworth Arnold - Algebra - 1920 - 390 pages
...coefficient of the second term is the index of the required power. In each succeeding term the coefficient is found by multiplying the coefficient of the preceding term by the exponent oj a in that term, and dividing by the number of the preceding term. IV. Signs of terms. If the binomial... | |
 | De Witt Carl Eggleston, Frederick Bertrand Robinson - Cost accounting - 1921 - 628 pages
...the first is am and the last is x**. 445 3. The coefficient of a term is obtained by multiplying tbe coefficient of the preceding term by the exponent of a in that term, and dividing the product by 1 plus the exponent of x in the same term. 487. Chart showing the Normal Curve of Error... | |
 | George Irving Gavett - Statistics - 1925 - 378 pages
...deriving any coefficient from the preceding coefficient: For the coefficient of any term, multiply the coefficient of the preceding term by the exponent of a in that term and divide by one more than the exponent of b. The exponent of b in the first term is 0, in the second... | |
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