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" ... terms. Hence, The sum of an arithmetical series may be found by multiplying one-half the sum of the first and last terms by the number of terms. Thus, the sum of eight terms of the series whose first term is 3, and last term 38, is EXERCISE LXXXVII.... "
A Practical Arithmetic - Page 308
by George Albert Wentworth, Thomas Hill - 1882 - 351 pages
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An Advanced Arithmetic for High Schools, Normal Schools, and Academies

George Albert Wentworth - Arithmetic - 1898 - 424 pages
...last terms. Hence, 616. To Find the Sum of the Terms of an Arithmetical Progression, Multiply one half the sum of the first and last terms by the number...the series whose first term is 3 and last term 38 is 8 X i (3 + 38) = 164. EXERCISE 147. 1. Find the sum of 1, 5, 9, etc., to twenty terms. 2. Find the...
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An Advanced Arithmetic for High Schools, Normal Schools, and Academies

George Albert Wentworth - Arithmetic - 1898 - 424 pages
...last terms. Hence, 616. To Find the Sum of the Terms of an Arithmetical Progression, Multiply one half the sum of the first and last terms by the number...the series whose first term is 3 and last term 38 is 8 X \ (3 + 38) = 104. EXERCISE 147. 1. Find the sum of 1, 5, 9, etc., to twenty terms. 2. Find the...
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Notes on Life Insurance: The Theory of Life Insurance Practically Explained ...

Edward Bathurst Fackler - Insurance, Life - 1907 - 216 pages
...arithmetical series multiplied by — , and the rule for finding the sum of such a series is: — "Multiply the sum of the first and last terms by the number of terms and divide the product by two." Here the first term (within brackets) and the last is ax. The number...
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Notes on Life Insurance, the Theory of Life Insurance Practically Explained ...

Edward Bathurst Fackler - Life insurance - 1920 - 216 pages
...arithmetical series multiplied by — , and the rule for finding the sum of such a series is : — " Multiply the sum of the first and last terms by the number of terms and divide the product by two." Here the first term (within brackets) is I + ax\ and the last is ox....
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