 | Commissioners of National Education in Ireland - Measurement - 1837 - 290 pages
...Ana. 1-41372. PROBLEM XXVIII. To find the area of the segment of a circle. MENSURATION OF SUPERFICIES. of the triangle, formed by the chord of the segment and the two radii of the sector. Then add these two areas together, when the segment is greater than a semi-circle, but find their difference... | |
 | Jeremiah Day - Geometry - 1838 - 416 pages
...the area of a SEGMENT of a circle. 35. FIND THE AREA OF THE SECTOR WHICH HAS THE SAME ARC, AND ALSO THE AREA OF THE TRIANGLE FORMED BY THE CHORD OF THE SEGMENT AND THE RADII OF THE SECTOR. THEN, IP THE SEGMENT BE LESS THAN A SEMI-CIRCLE, SUBTRACT THE AREA OF THE TRIANGLE... | |
 | Jeremiah Day - Geometry - 1839 - 434 pages
...the area of a SEGMENT of a circle. 35. FIND THE AREA OF THE SECTOR WHICH HAS THE SAME ARC, AND ALSO THE AREA OF THE TRIANGLE FORMED BY THE CHORD OF THE SEGMENT AND THE RADII OF THE SECTOR. THEN, IF THE SEGMENT BE LESS THAN A SEMI-CIRCLE, SUBTRACT THE AREA OF THE TRIANGLE... | |
 | Charles Davies - Geometrical drawing - 1840 - 262 pages
...RULE. 1st. Find the area of the sector having the same arc with the segment by the last Problem. 2d. Find the area of the triangle formed by the chord of the segment and the two radii through its extremities. 3d. If the segment is greater than the semicircle, add the two areas together... | |
 | Frederick Augustus Griffiths - 1840 - 436 pages
...find the Area of the Segment of a Circle. Find the area of the Sector, by the preceding Rule. Then find the area of the triangle formed by the chord of the segments, and the radii of the sector. Then, if the segment be less than a semicircle, subtract the... | |
 | Joseph Gwilt - Architects - 1842 - 1114 pages
...Hule 1. I-'ind the area of the sector having the same arc with the segment by the last problem. Then find the area of the triangle formed by the chord of the segment and the two radii of the sector. Take the sum of these two for the answer when the segment is greater than a semicircle, and their difference... | |
 | Charles Haynes Haswell - Engineering - 1844 - 298 pages
...Areas, page 72.) RULE 1. — Find the area of the sector having the same arc with the segment, then find the area of the triangle formed by the chord of the segment and the radii of the sector, and the difference of these areas, according as the segment is greater or less... | |
 | J. M. Scribner - Measurement - 1844 - 130 pages
...following rule is given in Day's Mathematics: Find the area of the sector which has the same arc, and also the area of the triangle formed by the chord of the segment and the radii of the sector. Then, if the segment be less than a semi-circle, subtract the area of the triangle... | |
 | William Watson (of Beverley.) - 1845 - 188 pages
...a circle. RULE. — Find the area of the sector which has the same arc with the segment : find also the area of the triangle formed by the chord of the segment, and the radii of the sector, then the difference or sum of these areas will be that of the segment, according... | |
 | Nathan Scholfield - 1845 - 894 pages
...of the segment of a circle. ROLE I. — Find the area of the sector which has the same arc, and also the area of the triangle formed by the chord of the segment and the radii of the sector. Then if the segment is less than a semicircle, subtract the area of the triangle... | |
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Find also the area of the triangle, formed by the chord of the segment and the two radii of the sector. 
