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" ... as many times as there are units in the exponent of the required power. Hence... "
An Elementary Treatise on Algebra: To which are Added Exponential Equations ... - Page 110
by Benjamin Peirce - 1837 - 284 pages
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College Algebra: For the Use of Academies, Colleges, and Scientific Schools ...

Edward Albert Bowser - Algebra - 1888 - 868 pages
...Hence the following RULE. Multiply the binomial by itself, until it has been taken as a factor as many times as there are units in the exponent of the required power. This rule, however, would be very laborious in finding any high power, for instance (a + 6)20. In Chapter...
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An Academic Arithmetic for Academies, High and Commercial Schools

Webster Wells - Arithmetic - 1893 - 382 pages
...to any required power (Art. 55). This may be effected by taking the given number as a factor as many times as there are units in the exponent of the required power (Art. 55). 1. Find the value of (f )4. We have, (£ Y = |x§xfx| = ^, А™. The following rule is...
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Essentials of Algebra for Secondary Schools

Webster Wells - Algebra - 1897 - 422 pages
...integer. This may be effected, as is evident from § 6, by taking the expression as a factor as many times as there are units in the exponent of the required power. INVOLUTION OF MONOMIALS. 186. 1. Find the value of (5a'Ь2)3. By § 6, (5<Л2)3 = 5oW x 5а'Ь2 x 5a3&3...
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Essentials of Algebra for Secondary Schools

Webster Wells - Algebra - 1897 - 384 pages
...integer. This may be effected, as is evident from § 6, by taking the expression as a factor as many times as there are units in the exponent of the required power. INVOLUTION OF MONOMIALS. 186. 1. Find the value of (5a?b*)3. By § 6, (5 a362)3 = 5 a362 x 5 a362 x...
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Essentials of Algebra for Secondary Schools

Webster Wells - Algebra - 1897 - 386 pages
...integer. This may be effected, as is evident from § 6, by taking the expression as a factor as many times as there are units in the exponent of the required power. INVOLUTION OF MONOMIALS. 186. 1. Find the value of (5 a^2)3. By § 6, (5 a8b2)8 = 5 Л* x 5 а8b2 x...
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