 | Charles Potts - Arithmetic - 1835 - 202 pages
...the numbers. To find the true remainder, multiply the last remainder by the second preceding divisor, and to the product add the preceding remainder ; multiply this sum by the fourth preceding divisor, and to the product add the preceding remainder, &c. through all the divisors... | |
 | Benjamin Greenleaf - Arithmetic - 1839 - 356 pages
...last remainder by the last divisor but one, and, to the product, add the next preceding remainder ; we multiply this sum by the next preceding divisor, and to the product add the next precedmg remainder; and so on, till we have gone through all the divisors and remainders to the first.... | |
 | Benjamin Greenleaf - Arithmetic - 1841 - 334 pages
...last remainder by the last divisor but one, and, to the product, add the next preceding remainder ; we multiply this sum by the next preceding divisor, and...add the next preceding remainder; and so on, till we have gone through all the divisors and remainders to the first. This rule will be better understood... | |
 | Benjamin Greenleaf - Arithmetic - 1842 - 184 pages
...last divisor but one, and to the product add the next preceding remainder; we multiply this product by the next preceding divisor, and to the product add the next preceding remainder ; and so on until we have gone through all the divisors and remainders to the first. 58. Divide 67895 by 24. 4... | |
 | Benjamin Greenleaf - Arithmetic - 1843 - 340 pages
...last remainder by the last divisor but one, and, to the product, add the next preceding remainder ; we multiply this sum by the next preceding divisor, and...add the next preceding remainder; and so on, till we have gone through all the divisors and remainders to the lirst. This rule will be better understood... | |
 | William Scott - Algebra - 1844 - 568 pages
...all the remainders into one is perfectly general : Multiply the last remainder by the last divisor but one, and to the product add the preceding remainder...and to the product add the next preceding remainder ; repeat this process until all the divisors and remainders are included. The last result is the number... | |
 | Benjamin Greenleaf - Arithmetic - 1844 - 352 pages
...last remainder by the last divisor but one, and, to the product, add the next preceding remainder ; we multiply this sum by the next preceding divisor, and...product add the next preceding remainder; and so on, tiU we have gone through all the divisors and remainders to the first. This rule will be better understood... | |
 | Benjamin Greenleaf - Arithmetic - 1844 - 208 pages
...and so continue ; and the last quotient will be the answer. ing remainder; we multiply this product by the next preceding divisor, and to the product add the next preceding remainder ; and so on until we have gone through all the divisors and remainders to the first. 58. Divide 67872 by 24. OPERATION.... | |
 | Benjamin Greenleaf - Arithmetic - 1844 - 204 pages
...last divisor but one, and to the product add the next preceding remainder; we multiply this product by the next preceding divisor, and to the product add the next preceding remainder ; and BO on until we have gone through all the divisors and remainders to the first. 58. Divide 67872 by... | |
 | Benjamin Greenleaf - Arithmetic - 1845 - 226 pages
...last divisor but one, and to the product add the next preceding remainder; we multiply this product by the next preceding divisor, and to the product add the next preceding remainder ; and so on until we have gone through all the divisors and remainders to the first. 58. Divide 67872 by 24. ,... | |
| |
Or multiply the last remainder by the preceding divisor, or last but one, and to the product add the preceding remainder; multiply this sum by the next preceding divisor, and to the product add the next preceding remainder ; and so on till you have gone... 
