 | Fletcher Durell - Algebra - 1916 - 606 pages
...1; of the second term it is the index of the required power. In each succeeding term the coefficient is found by multiplying the coefficient of the preceding term by the exponent of « in that term, and dividing by the number of the preceding term. IV. Signs of terms. If the binomial... | |
 | Herbert Ellsworth Slaught, Nels Johann Lennes - Algebra - 1917 - 674 pages
...one. The coefficient of the second term is the same as the index of the power. The coefficient of each succeeding term is found by multiplying the coefficient of the preceding term by the exponent of the first letter in that term and dividing by the exponent of the second letter increased by one. »Articles... | |
 | Ernst Rudolph Breslich - Logarithms - 1917 - 408 pages
...determined by means of the coefficient of the term just preceding, according to the following rule: Multiply the coefficient of the preceding term by the exponent of a in that term and divide the product by the number of that term. Thus in (a+6)6 the coefficient of the fifth term is... | |
 | Joseph Victor Collins - Algebra - 1918 - 360 pages
...the exponent of (a — A) in the left member ; also that each succeeding coefficient can be obtained by multiplying the coefficient of the preceding term by the exponent of the leading letter a, and dividing the product by the exponent of the other letter increased by 1.... | |
 | Julius Lederer Neufeld - Algebra - 1920 - 412 pages
...coefficient of the second term is equal to the exponent of the first term. 5. The coefficient of each succeeding term is found by multiplying the coefficient of the preceding term by the exponent of a and dividing that product by one more than the exponent of b. 6. In finding any power of o — 6, the... | |
 | Fletcher Durell, Elmer Ellsworth Arnold - Algebra - 1920 - 390 pages
...coefficient of the second term is the index of the required power. In each succeeding term the coefficient is found by multiplying the coefficient of the preceding term by the exponent oj a in that term, and dividing by the number of the preceding term. IV. Signs of terms. If the binomial... | |
 | George Irving Gavett - Statistics - 1925 - 378 pages
...deriving any coefficient from the preceding coefficient: For the coefficient of any term, multiply the coefficient of the preceding term by the exponent of a in that term and divide by one more than the exponent of b. The exponent of b in the first term is 0, in the second... | |
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... may be found by multiplying the coefficient of the preceding... 
