| Edward Brooks - Algebra - 1888 - 190 pages
...Adding the partial 2a2 — ab products, we have 2a2+3a6- 262. Therefore, etc. +4a6-26' 2a2 + 3a6-26« Rule. — Multiply each term of the multiplicand by each term of the multiplier, and add the partial products. a — 6 a +6 a2-a6 +a6-62 a3 -62 (6.) an-6" a2-6' a8 -62 an+Ja"68-a26"+6"+3 7. Multiply... | |
| Edward Albert Bowser - Algebra - 1888 - 868 pages
...Art. 38] = oc— ad— bc+bd (Art. 33). . . (4) Hence, to multiply one polynomial by another, we have the following RULE. Multiply each term of the multiplicand by each term of the multiplier; if the terms multiplied together have the same sign, prefix the sign + to the product, if unlike, prefix... | |
| Horatio Nelson Robinson - 1888 - 372 pages
...I. Write the several terms of the multiplier under the corresponding terms of the multiplicand. II. Multiply each term of the multiplicand by each term of the multiplier, beginning with the lowest term in each, an I call the product of any two denominations the denomination... | |
| William Frothingham Bradbury, Grenville C. Emery - Algebra - 1889 - 428 pages
...by-\-bz. Hence, for the multiplication of a polynomial by a polynomial, we have the following Ru1e. • Multiply each term of the multiplicand by each term of the multiplier, and find the sum of the several products. 2. Multiply 2 x2 + 3 xy — if by 3 x — 2 y. 2x* + 3xy —... | |
| Webster Wells - Algebra - 1890 - 560 pages
...of Polynomials by Polynomials. By Art. 60, (1), = ac + be + ad + bd, by Art. 60, (5). "We then have the following rule : Multiply each term of the multiplicand by each term of the multiplier, and add the partial products. 1. Multiply 3a - 2 b by 2a - 56. In accordance with the rule, we multiply 3a— 2b... | |
| George Albert Wentworth - Algebra - 1890 - 376 pages
...=am-\-an-\-ap-\-bm-\-bn-\-bp-\-cm-\-cn-}-cp. To find the product of two polynomials, therefore, Multiply every ierrn of the multiplicand by each term of the multiplier, and add the partial products. 69. In multiplying polynomials, it is a convenient arrangement to write the multiplier... | |
| George Albert Wentworth - Algebra - 1891 - 380 pages
...-(-p) + с ( w + i = am+aи4- ap4-6 That is, to find the product of two polynomials, ' Multiply every term of the multiplicand by each term of the multiplier, and add the partial products. 69. In multiplying polynomials, it is a convenient arrangement to write the multiplier... | |
| George Albert Wentworth - Algebra - 1891 - 550 pages
...ap + 6m + bn + ¿p + сw + cn + cp. That is, to find the product of two polynomials, Multiply every term of the multiplicand by each term of the multiplier, and add the partial products. 64, In multiplying polynomials, it is a convenient arrangement to write the multiplier... | |
| William James Milne - Algebra - 1892 - 370 pages
...-5a* — 5aж 3a2*3" 35. 36. 37. 38. Multiply 2 иs" By 4а*-ÏS :45Í? 3aГ i -5ж*+3 MULTIPLICATION. RULE. — Multiply each term of the multiplicand by each term of the multiplier, and add the partial products. 2. 3. Multiply ab + 2c 3 ж2 - (m/ By 2ab — 3c -3а&с-6с2 Product, 2a2b2+ а&с-6с2... | |
| George W. Lilley - Algebra - 1892 - 420 pages
...i5 +10 1» -5z -25 i10 + 2 z» -г 7 г« -«i4-3x" - 15x8+ 10x2-5;r- ¿5 Explanation. Multiplying each term of the multiplicand by each term of the multiplier and connecting these results with their proper signs, we have г10 - r' + 2x* - з* - 5 x* + 3 i» - ЗА... | |
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