Hidden fields
Books Books
" Multiply each term of the multiplicand by each term of the multiplier, and add the partial products. "
The Collegiate Algebra: Adapted to Colleges and Universities - Page 39
by James Bates Thomson, Elihu Thayer Quimby - 1880 - 346 pages
Full view - About this book

The Normal Elementary Algebra: Containing the First Principles of the ...

Edward Brooks - Algebra - 1888 - 190 pages
...Adding the partial 2a2 — ab products, we have 2a2+3a6- 262. Therefore, etc. +4a6-26' 2a2 + 3a6-26« Rule. — Multiply each term of the multiplicand by each term of the multiplier, and add the partial products. a — 6 a +6 a2-a6 +a6-62 a3 -62 (6.) an-6" a2-6' a8 -62 an+Ja"68-a26"+6"+3 7. Multiply...
Full view - About this book

College Algebra: For the Use of Academies, Colleges, and Scientific Schools ...

Edward Albert Bowser - Algebra - 1888 - 868 pages
...Art. 38] = oc— ad— bc+bd (Art. 33). . . (4) Hence, to multiply one polynomial by another, we have the following RULE. Multiply each term of the multiplicand by each term of the multiplier; if the terms multiplied together have the same sign, prefix the sign + to the product, if unlike, prefix...
Full view - About this book

Robinson's Progressive Practical Arithmetic: Containing the Theory of ...

Horatio Nelson Robinson - 1888 - 372 pages
...I. Write the several terms of the multiplier under the corresponding terms of the multiplicand. II. Multiply each term of the multiplicand by each term of the multiplier, beginning with the lowest term in each, an I call the product of any two denominations the denomination...
Full view - About this book

The Academic Algebra

William Frothingham Bradbury, Grenville C. Emery - Algebra - 1889 - 428 pages
...by-\-bz. Hence, for the multiplication of a polynomial by a polynomial, we have the following Ru1e. • Multiply each term of the multiplicand by each term of the multiplier, and find the sum of the several products. 2. Multiply 2 x2 + 3 xy — if by 3 x — 2 y. 2x* + 3xy —...
Full view - About this book

College Algebra

Webster Wells - Algebra - 1890 - 560 pages
...of Polynomials by Polynomials. By Art. 60, (1), = ac + be + ad + bd, by Art. 60, (5). "We then have the following rule : Multiply each term of the multiplicand by each term of the multiplier, and add the partial products. 1. Multiply 3a - 2 b by 2a - 56. In accordance with the rule, we multiply 3a— 2b...
Full view - About this book

A School Algebra

George Albert Wentworth - Algebra - 1890 - 376 pages
...=am-\-an-\-ap-\-bm-\-bn-\-bp-\-cm-\-cn-}-cp. To find the product of two polynomials, therefore, Multiply every ierrn of the multiplicand by each term of the multiplier, and add the partial products. 69. In multiplying polynomials, it is a convenient arrangement to write the multiplier...
Full view - About this book

A School Algebra

George Albert Wentworth - Algebra - 1891 - 380 pages
...-(-p) + с ( w + i = am+aи4- ap4-6 That is, to find the product of two polynomials, ' Multiply every term of the multiplicand by each term of the multiplier, and add the partial products. 69. In multiplying polynomials, it is a convenient arrangement to write the multiplier...
Full view - About this book

A Higher Algebra

George Albert Wentworth - Algebra - 1891 - 550 pages
...ap + 6m + bn + ¿p + сw + cn + cp. That is, to find the product of two polynomials, Multiply every term of the multiplicand by each term of the multiplier, and add the partial products. 64, In multiplying polynomials, it is a convenient arrangement to write the multiplier...
Full view - About this book

High School Algebra: Embracing a Complete Course for High Schools and Academies

William James Milne - Algebra - 1892 - 370 pages
...-5a* — 5aж 3a2*3" 35. 36. 37. 38. Multiply 2 иs" By 4а*-ÏS :45Í? 3aГ i -5ж*+3 MULTIPLICATION. RULE. — Multiply each term of the multiplicand by each term of the multiplier, and add the partial products. 2. 3. Multiply ab + 2c 3 ж2 - (m/ By 2ab — 3c -3а&с-6с2 Product, 2a2b2+ а&с-6с2...
Full view - About this book

The Elements of Algebra

George W. Lilley - Algebra - 1892 - 420 pages
...i5 +10 1» -5z -25 i10 + 2 z» -г 7 г« -«i4-3x" - 15x8+ 10x2-5;r- ¿5 Explanation. Multiplying each term of the multiplicand by each term of the multiplier and connecting these results with their proper signs, we have г10 - r' + 2x* - з* - 5 x* + 3 i» - ЗА...
Full view - About this book




  1. My library
  2. Help
  3. Advanced Book Search
  4. Download EPUB
  5. Download PDF