 | D. M. Knapen - Measurement - 1849 - 300 pages
...the rules for the triangle. See ^[19, under problem 10. The sum of all the angles of any polygon is equal to twice as many right angles, wanting four, as the figure has sides ; and when the polygon is regular, if the sum of the angles be divided by the number of angles, the... | |
 | Elias Loomis - Conic sections - 1849 - 252 pages
...of one right angle. PROPOSITION XXVIII. THEOREM. The sum of all the interior angles of a polygon, is equal to twice as many right angles, wanting four, as the figure has sides. angles of each of these triangles, is equal to two right angles (Prop. XXVII.); therefore the sum of... | |
 | Charles Davies - Geometry - 1850 - 218 pages
...the angles of the triangles, before found. Hence, the sum of the interior angles of the polygon is equal to twice as many right angles, wanting four, as the figure has sides. Sch. This proposition is not applicable to polygons which have re-entrant angles. The reasoning is... | |
 | Charles Davies - Geometry - 1850 - 238 pages
...the angles of the triangles, before found. Hence, the sum of the interior angles of the polygon is equal to twice as many right angles, wanting four, as the figure has sides. Sch. This proposition is not applicable to polygons which have re-entrant angles. The reasoning is... | |
 | Charles Davies - Geometry - 1886 - 340 pages
...side Of Polygons Let ABCDE be any polygon: then will the sum of its inward angles A+B+C+D+E be equ1l to twice as many right angles, wanting four, as the figure has sides. For, from any point P, within the poly. AB gon, draw the lines PA, PB, PC, PD, PE, to each cf the angles,... | |
 | Charles Davies - Geometry - 1855 - 340 pages
...the angles of the triangles, before found- Hence, the sum of the interior angles of the polygon is equal to twice as many right angles, wanting four, as the figure IMS sidesSch This proposition is not applicable to polygons which have re-entrant anglesThe reasoning... | |
 | Elias Loomis - Conic sections - 1858 - 256 pages
...figure has sides. Let ABCDE be any polygon ; then the sum of all its interior angles A, B, C, D, E is equal to twice as many right angles, wanting four, as the figure has sides (see next page). For, from any point, F, within it, draw lines FA, FB, FC, &c , to all the angles.... | |
 | Anthony Nesbit - Measurement - 1859 - 494 pages
...formed. NOTE. — The sum of all the interior angles of any polygon, whether regular or irregular, is equal to twice as many right angles, wanting four, as the figure has sides. PROBLEM XXVHI. To find a mean proportional between two given lines, Let the given lines be AB = 32,... | |
 | William Grier - Mechanical engineering - 1861 - 316 pages
...right angles. 19. Let ABCDE be any figure ; then the sum of all its inward angles, A+B + C+DfE, is equal to twice as many right angles, wanting four, as the figure has sides. t 20. Let A, B. C, &c., be the outward angles of any polygon, made by producing all the sides; then... | |
 | Evan Wilhelm Evans - Geometry - 1862 - 116 pages
...polygon is the sum of all its sides. 36 GEOMETRY. THEOKEM XX. The sum of all the angles of any polygon is equal to twice as many right angles, wanting four, as the figure has sides. Let ABODE be any polygon. It is to be proved that the sum of all its angles A, B, C, D, E, is equal... | |
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Angles, taken together, is equal to Twice as many Right Angles, wanting four, as the Figure has Sides. 
