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" The complements of the parallelograms, which are about the diameter of any parallelogram, are equal to one another. "
Elements of Geometry, Containing the First Six Books of Euclid - Page 33
by Euclid - 1826 - 180 pages
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Gradations in Euclid : books i. and ii., with an explanatory preface [&c ...

Euclides - 1870 - 270 pages
...Prop. 41 equal to the parallelogram FECG. , PROP. 43. — THEOR. The complements of the parallelograms which are about the diameter of any parallelogram, are equal to one anotlier. DKM. — P. 34. The opposite sides and angles of parallelograms are equal, and the diameter...
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Elements of geometry, containing the first two (third and fourth ..., Part 1

Euclides - 1871 - 136 pages
...of the same altitude with, and equal to, the given triangle. The complements of the parallelograms, which are about the diameter of any parallelogram, are equal to one another. Let ABCD be a O, of which BD is a diagonal, and EG, HK the Os about BD, that is, through which BD passes, and AF,...
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Elements of geometry, containing books i. to vi.and portions of books xi ...

Euclides, James Hamblin Smith - Geometry - 1872 - 376 pages
...and cqua1 to, the given triangle. PROPOSITION XLIII. THEOREM. The complements of the parallelograms, which are about the diameter of any parallelogram, are equal to one another. Let ABCD be a O, of which BD is a diagonal, and EG, HK the Os about BD, that is, through which BD passes, and AF,...
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The Acting Teacher's and Student's in Training Guide and Text Book for ...

Henry Major - Student teachers - 1873 - 588 pages
...triangle ABC, and it has one of its angles CEF equal to the given angle D, A. TJ . — The complements about the diameter of any parallelogram, are equal to one another. Let ABCD be a parallelogram, of -which the diameter is AC, and EH, FG, the parallelograms about AC, and BK, KD, the other parallelograms...
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The Elements of Euclid, containing the first six books, with a selection of ...

Euclides - 1874 - 342 pages
...CEF equal to the given angle DQEF PROPOSITION 43.— Theorem. The complements of the parallelograms, which are about the diameter of any parallelogram,...equal to one another. Let ABCD be a parallelogram, of which the diameter is AC ; and EH, GF the parallelograms about AC, that is, through which AC passes...
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Euclidian Geometry

Francis Cuthbertson - Euclid's Elements - 1874 - 400 pages
...having equal bases and altitudes, are equal. PROPOSITION XXXIV. The complements of the parallelograms, which are about the diameter of any parallelogram, are equal to one another. Let FGHK be a O-, and GK one of its diagonals, and SR, PN Os about the diagonal. Then FQ, QH, the remaining...
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Pure mathematics, Volume 1

Edward Atkins - 1874 - 428 pages
...(Const.). Proposition 43.— Theorem. 17ie complements of the parallelograms which are about the diagonal of any parallelogram are equal to one another. Let ABCD be a parallelogram, of which the diagonal is AC ; and EH, GF parallelograms about AC, that is, through which AC passes...
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Recent Military, Naval, and Civil Service Examination Papers in Mathematics ...

Braithwaite Arnett - 1874 - 130 pages
...sides equal to them of the other. 2. Define a parallelogram. The complements of the parallelograms which are about the diameter of any parallelogram are equal to one another. In the case of a square, if the squares about the diameter are 169 and 625 square feet in area, what...
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A school Euclid, being books i. & ii. of Euclid's Elements, with notes by C ...

Euclides - 1874 - 120 pages
...given rightangled isosceles triangle. PROPOSITION 43. THEOREM. The complements of the parallelograms which are about the diameter of any parallelogram, are equal to one another. j Let ABCD be a parallelogram, of which the '• diameter is AC; and EH, GF parallelograms about AC,...
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The Pupil teacher, a monthly educational journal. H. Major, ed

Henry Major - 1876 - 784 pages
...perpendicular, and the remaining side, will form an equilateral triangle. 2. The complements of the parallelogram, which are about the diameter of any parallelogram, are equal to one another. 1. Divide 189**-9h:32/ + 62a;y-13,^3 + 5i/ by 27x2-13xy-r5y"-. 2. Find the GCM of 7*2-23a:-t-6 and...
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