 | Benjamin Greenleaf - Arithmetic - 1858 - 332 pages
...in the left-hand period, and place its root on the right. Subtract the cube, thus found, from this period, and to the remainder bring down the next period for a dividend. Multiply the square of the root already found by 300 for a divisor, by which divide the dividend, and... | |
 | Benjamin Greenleaf - Arithmetic - 1858 - 456 pages
...period, and trrite its root as the jirst figure of the required root. From that period subtract the cube, and to the remainder bring down the next period for a dividend. Multiply the, square of the root figure by 3, and to the product annex tiro ciphers for a trial diviior,... | |
 | Charles Haynes Haswell - Measurement - 1858 - 350 pages
...left-hand period, and place its root in the quotient ; subtract the square number from the left-hand period, and to the remainder bring down the 'next period for a new dividend. Double the root already found for a divisor ; find how many times this incomplete divisor... | |
 | Horatio Nelson Robinson - Arithmetic - 1859 - 362 pages
...left hand period, and write its root for the first figure in the root ; subtract the square number from the left hand period, and to the remainder bring down the next period for a dividend. Fig. III. 70 i Two Divisors = 140 1 70. 3 Complete Divisor = 143 III. At the left of the dividend write... | |
 | Horatio Nelson Robinson - Arithmetic - 1860 - 444 pages
...left hand period, and write its root for the first figure in the required root; subtract, the cube from the left hand period, and to the remainder bring down the next period for a dividend. III. At the left of the dividend write three times the square of tlie first figure of the root, and-... | |
 | Dana Pond Colburn - Arithmetic - 1860 - 388 pages
...hand period, and place its root as the first figure of the required root. Third. Subtract this cube from the left hand period, and to the remainder bring down the next period, calling the result a dividend. Fourih. Find three times tlie square of the part of the root already... | |
 | Daniel Adams - Arithmetic - 1861 - 452 pages
...period, and write its root as a quotient in division. Subtract the square number from the left-hand period, and to the remainder bring down the next period for a dividend. III. Double the root already found for a divisor ; seek how many times the divisor is contained in... | |
 | Benjamin Greenleaf - Arithmetic - 1861 - 338 pages
...in the left-hand period, and place its root on the right. Subtract the cube, thus found, from this period, and to the remainder bring down the next period for a dividend. RULE. — Separate the given number into as many periods as possible of three figures each, by placing... | |
 | John Flint (inspector of schools.) - 1862 - 152 pages
...in the left hand period, and write its cube root as the first figure of the root. Subtract its cube from the left hand period, and to the remainder bring down the next period for a dividend. Multiply the square of the part of the root found by 300 for a trial divisor ; divide the dividend... | |
 | Benjamin Greenleaf - 1863 - 338 pages
...the left-hand period, and place its root on the right ; subtract the cube of this root from the first period, and to the remainder bring down the next period for a dividend. At the left of the dividend write three times the square ofth* root already found, for a trial divisor... | |
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Subtract the square number from the left hand period, and to the remainder bring down the next period for a dividend. III. Double the root already found for a divisor ; seek how many times the divisor is contained in the dividend... 
