 | Charles Davies - Arithmetic - 1850 - 412 pages
...1.—When any decimal number is to be divided by 10, 100, 1000, &c., the division is made by removing the decimal point as many places to the left as there are O's in the divisor ; and if there be not so many figures on the left of the decimal point, the deficiency... | |
 | Calvin Tracy - 1851 - 214 pages
...marked +, implying more. (See 4th sum.) § 90, — To divide a decimal by 10, 100, 1000, &c. RULE. Remove the decimal point as many places to the left as there are ciphers in the divisor. 1. Divide 30515.50 by 100. Ans. 305.1550. 2. Divide 36.5 by 10. Ans. 3.65. 3. Divide 36.10 by 100.... | |
 | George Roberts Perkins - Arithmetic - 1851 - 356 pages
...by 0-4051. Ans. 2-223+. Sf. We may, obviously, divide any decimal by 10, 100, 1000, &c., by removing the decimal point as many places to the left as there are ciphers in the divisor; when there are not so many figures at the left of the decimal point, we may prefix ciphers. 10 100... | |
 | Dana Pond Colburn - Arithmetic - 1852 - 228 pages
...used in writing the given multiplier. To express the quotient of a number divided by any power of 10, remove the decimal point as many places to the left as there are zeros used in writing the given divisor. When, by such change, any places between the number and point... | |
 | John Hunter - Arithmetic - 1852 - 184 pages
...as a divisor, the quotient may be represented by merely shifting the decimal point of the dividend as many places to the left as there are ciphers in the divisor. Thus, * 860-=- 100 = 860-0 -r- 100 = 8'6; 45 -4- 1000 = 45-0 -4- 1000 = -045; 23-47 -h 10000 = -002347.... | |
 | William Frederick Greenfield - 1853 - 228 pages
...figures to the left of the point, then (Cor. 1 Prop. 37) ciphers must be supplied. Hence the Rule : remove the decimal point as many places to the left as there are ciphers in the denominator, supplying ciphers if necessary. Prop 41. — To prove the Rule for Multiplication of Decimals.... | |
 | David Henry Cruttenden - Arithmetic - 1853 - 330 pages
...the remainders as if added to the dividend. If the divisor be 10 or 100, etc., simply removing the point as many places to the left, as there are ciphers in the divisor, completes the division. (See Case V., Remark.) 17. Divide .192816 by .312. Ans. .618. 18. Divide 1.28... | |
 | Chambers W. and R., ltd - 1854 - 152 pages
...NOTE. — To DIVIDE by lO, 100, or 1 with any other number of nothings annexed, it is only necessary to remove the decimal point as many places to the left as there are nothings in the divisor; thus— 124-5 divided by 100, becomes 1-245. Exercises, 1. Divide 231-0 by... | |
 | Horace Mann - 1855 - 272 pages
...decimals in the quotient as there are in the dividend more than in the divisor. S3. To divide any number by 10, 100, 1000, &c., remove the decimal point as many places to the left as there are zeroes in the divisor. q* When there are zeroes at the right hand of the divisor, cut them off, and... | |
 | George Roberts Perkins - Arithmetic - 1855 - 388 pages
...by 0-4051. Ans. 2-223+. 57. We may, obviously, divide any decimal by 10, 100, 1000, &c., by removing the decimal point as many •places to the left as there are ciphers in the divisor ; when there are not so many figures at the left of the decimal point, we may prefix ciphers. 10 100... | |
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When a decimal number is to be divided by 10, 100, 1000, &c., remove the decimal point as many places to the left as there are ciphers in the divisor, and if there be not figures enough in the number, prefix ciphers. 
