 | Benjamin Greenleaf - 1863 - 338 pages
...the left-hand period, and place its root on the right ; subtract the cube of this root from the first period, and to the remainder bring down the next period for a dividend. At the left of the dividend write three times the square ofth* root already found, for a trial divisor... | |
 | Horatio Nelson Robinson - Algebra - 1863 - 432 pages
...wríte its root for the first figure in the root sought ; subtract the square number from the left-hand period, and to the remainder bring down the next period for a dividend. III. At the left of the dividend write twice the first figure, of the root, for a trial divisor ; divide... | |
 | George Augustus Walton - Arithmetic - 1864 - 376 pages
...hand period, and write its root as the first term in the answer. Subtract the cube from the left hand period, and to the remainder bring down the next period for a dividend. Multiply the square of the root already found, considered as tens, by three for a trial divisor. Divide... | |
 | George Augustus Walton - Arithmetic - 1864 - 364 pages
...hand period, and write its root as the first term in the answer. Subtract the cube from the left hand period, and to the remainder bring down the next period for a dividend. Multiply the square of the root already found, considered as tens, by three for a trial divisor. Divide... | |
 | Elias Loomis - Algebra - 1864 - 386 pages
...first period, and to the remainder bring down the second period for a dividend. 3. Take three hundred times the square of the root already found for a trial divisor; find how many times it is contained in the dividend, anyplace the quotient for a second figure of the... | |
 | Joseph Ray - Algebra - 1852 - 422 pages
...period, and place its root on the right, as in division. Subtract the cube of the root from the left period, and to the remainder bring down the next period for a dividend. 3rd. Square the root already found, and multiply it by 3 for a trial divisor. Find how many times this... | |
 | Joseph Ray - Algebra - 1866 - 250 pages
...the right, after the manner of a quotient in division. Subtract the square of the root from the left period, and to the remainder bring down the next period for a dividend. 3. Double the root already found, and place it on the left for a divisor. Find how many times the divisor... | |
 | Horatio Nelson Robinson - Algebra - 1866 - 328 pages
...root for the first figure in the required root ; subtract the square of this figure from the first period, and to the remainder bring down the -next period for a dividend. III. Double the root already found, and write the result on the left for a divisor ; find how many... | |
 | Joseph Ray - Algebra - 1866 - 420 pages
...period, and place its root on the right, as in division. Subtract the cube of the root from the left period, and to the remainder bring down the next period for a dividend. 3d. Square the root already found, and multiply it by 3 for a trial divisor. Find how many times this... | |
 | Robert Thomson (of Southampton.) - Marine engineers - 1866 - 180 pages
...number : cube this figure placed in the quotient and place its product under the first period, subtract and to the remainder bring down the next period for a dividend. Example 1st. — Extract the cube or third root of 312908547060. 6x6=36 6x3=18x6= 10800 187x7= 1309... | |
| |
... and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found, on the left hand of the dividend for a divisor. 
