 | Pliny Earle Chase - 1844 - 258 pages
...left hand period, and subtract the cube from the period, annexing the second period to the remainder. Take three times the square of the root already found, for a trial divisor, and find how many times this divisor is contained in the hundreds of the dividend. Place the result... | |
 | Charles Haynes Haswell - Engineering - 1844 - 298 pages
...left-hand period, and plnce Its root in the quotient; subtrnct the square number from the left-hand period, and to the remainder bring down the next period for a dividend. Double the root already found for a divisor ; find how many times the divisor is contained in the dividend,... | |
 | Benjamin Greenleaf - Arithmetic - 1844 - 204 pages
...for the first figure of the root, and the square number under the period, and subtract it therefrom, and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found, on the left hand of the dividend for a divisor. 4. Seek... | |
 | Benjamin Greenleaf - Arithmetic - 1844 - 208 pages
...for the first figure of the root, and the square number under the period, and subtract it therefrom, and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found, on the left hand of the dividend for a divisor. 4. Seek... | |
 | Arithmetic - 1845 - 210 pages
...period, and set its root on the right of the given number: subtract said square from the left hand period, and to the remainder bring down the next period for a dividual. 3. Double the root for a divisor, and try how often this divisor (with the figure used in... | |
 | Almon Ticknor - Arithmetic - 1846 - 276 pages
...place <he root to the right of the given number, and subtract the cube of the root from the left hand period, and to the remainder bring down the next period for a dividend. 3. Square the root, and multiply it by three for a defective divisor. 4. Reserve mentally the units... | |
 | James Bates Thomson - Arithmetic - 1846 - 362 pages
...2 on the right of the given number for tke first figure in the root, we subtract its cube from the period, and to the remainder bring down the next period for a dividend. This shows that we have 7625 solid feet to be added to the cubical mound already found. 3. We square... | |
 | James Bates Thomson - Arithmetic - 1846 - 354 pages
...placing its root on the right of the number for the first figure of the root, subtract its cube from the period, and to the remainder bring down the next period for a dividend. III. Square the root already found, giving it its true local value ; multiply this square by 3, and... | |
 | James Bates Thomson - Arithmetic - 1846 - 402 pages
...placing its root on the right of the number for the first figure of the root, subtract its cube from the period, and to the remainder bring down the next period for a dividend. III. Square the root already found, giving it its true local value ; multiply this square by 3, and... | |
 | Pliny Earle Chase - Arithmetic - 1848 - 244 pages
...left hand period, and subtract the cube from the period, annexing the second period to the remainder. Take three times the square of the root already found, for a trial divisor, and find how many times this divisor is contained in the hundreds of the dividend. Place the result... | |
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... and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found, on the left hand of the dividend for a divisor. 
