 | James L. Connolly (mathematician.) - Arithmetic - 1829 - 266 pages
...not too great, of the first period, for the first figure of your root, subtract its cube from said period, and to the remainder bring down the next period for a resolvend. Take three times the square of the root for a defective divisor, and seek how often it is... | |
 | Daniel Adams - Arithmetic - 1830 - 268 pages
...period, and write its root as a quotient in division. Subtract the square number from the left hand period, and to the remainder bring down the next period for a dividend. III. Double the root already found for a divisor; seek how many times the divisor is contained in the... | |
 | Daniel Adams - Arithmetic - 1830 - 294 pages
...period, and write its root as a quotient in division. Subtract the square number from the left haud period, and to the remainder bring down the next period for a dividend. III. Double the root already found for a divisor; seek how many times the divisor is contained in the... | |
 | Frederick Augustus Porter Barnard - Arithmetic - 1830 - 304 pages
...SUBTRACT FROM THE HIGHEST PERIOD THE GREATEST SQUARE CONTAINED IN IT, PLACE THE ROOT IN THE QUOTIENT, AND TO THE REMAINDER BRING DOWN THE NEXT PERIOD FOR A DIVIDEND. II. DotlBI.E THE ROOT ALREADY FOUND, (UNDERSTANDING A CYPHER AT THE RIGHT,} FOR A DIVISOR, AND DIVIDE... | |
 | Daniel Adams - Arithmetic - 1831 - 276 pages
...period, and write its root as a quotient in division. Subtract the square number from the left hand period, and to the remainder bring down the next period for a dividend. III. Double the root already found for a divisor ; seek how many times the divisor is contained in... | |
 | Martin Ruter - Arithmetic - 1831 - 190 pages
...in the left hand period, place the root of it in the quotient, subtract the cube from the left hand period, and to the remainder bring down the next period for a resolvend. 3. Square the quotient and multiply the square by 3 for a defective divisor. 4. Seek how... | |
 | William Kinne - Accounting - 1831 - 248 pages
...for the first figure of the root; and set the square number under the period, subtract it therefrom, and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found on the left hand of the dividend for a divisor. 4. Consider... | |
 | Zadock Thompson - Arithmetic - 1832 - 186 pages
...highest figure in the root required. Subtract the square of the root already found from the left hand period, and to the remainder bring down the next period for a dividend. Double the root already found for a divisor; seek how many times the divisor is contained in the dividend... | |
 | Samuel Read Hall - Arithmetic - 1832 - 294 pages
...highest figure in the root required. Subtract the square of the root already found from the left hand period, and to the remainder bring down the next period for a dividend. Double the root already found for a divisor ; seek how many times the divisor is contained in the dividend,... | |
 | Zadock Thompson - Arithmetic - 1832 - 186 pages
...cube in the left hand period, and place its root in the quotient. Subtract the cube from the left hand period, and to the remainder bring down the next period for a dividend. Multiply the square of the quotient by 300, calling it the triple square, and the quotient by 30, calling... | |
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... and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found, on the left hand of the dividend for a divisor. 
