 | Edward Richard Shaw - Examinations - 1887 - 360 pages
...— i 244. That which has length and breadth only. 245. Multiply the base by half the altitude. 246. From half the sum of the three sides subtract each side separately, multiply the half sum and the three remainders together, and extract the square root of the product.... | |
 | W. V. Wright - Measurement - 1887 - 76 pages
...Divide the circumference by 3.14159. When the three sides of a triangle are given, to find the area : From• half the sum of the three sides subtract each side separately. Multiply the half-sum and the three remainders together, and extract the square root of the product.... | |
 | Charles Scott Venable - Arithmetic - 1888 - 402 pages
...equals half of the product of either side by the perpendicular to it from the opposite vertex; or, from half the sum of the three sides subtract each side separately ; multiply together the half sum and the three remainders ; and the square root of the product is the... | |
 | Andrew Jackson Rickoff - 1888 - 464 pages
...following rule is sometimes necessary : When the three sides of a triangle are given, to find the area: From half the sum of the three sides subtract each side separately. Multiply the half sum and the three remainders together, and extract the square root of the product.... | |
 | Thomas A. Rice - Accounting - 1889 - 364 pages
...Multiply three sides together. 6. To find area of triangle. — Multiply base by half the altitude. Or, from half the sum of the three sides subtract each side separately ; multiply the half sum by the three remainders, and extract square root of product. 7. To find area... | |
 | Horatio Nelson Robinson - Arithmetic - 1892 - 428 pages
...= 60 ; 60 - 30 = 30 ; 60 - 40 = 20; 60 - 50 = 10. \X60~x30 x 20 x 10 = 600 sq. ft., area. RULE. — From half the sum of the three sides subtract each side separately; multiply the half-sum and the three remainders together; the square root of the product is the area.... | |
 | Horatio Nelson Robinson - Arithmetic - 1892 - 428 pages
...2 = 60 ; 60 - 30 = 30 ; 60 - 40 = 20 ; 60 - 50 = 10. V60x30x20xlo' = 600 sq. ft. , area. RULE. — From half the sum of the three sides subtract each side separately ; multiply the half-sum and the three remainders together; the square root of the product is the area.... | |
 | Massachusetts - Massachusetts - 1893 - 988 pages
...product of the side and perpendicular, and divide by 160. (ft) When three sides are given. Rule. — From half the sum of the three sides subtract each side separately ; multiply the half sum and the three remainders together; the square root of the product divided by... | |
 | George Washington Hull - Arithmetic - 1895 - 408 pages
...if the three sides of a triangle are given and not the altitude, the area can be found as follows : From half the sum of the three sides subtract each side separately ; multiply the half sum and the three remainders together, and extract the square root of the product... | |
 | Horatio Nelson Robinson - Arithmetic - 1895 - 526 pages
...= GO ; CO - 30 = 30 ; 60 - 40 = 20 ; 60 - 50 = 10. V60 x 30 x 20 x 10 = 600 ft, area Ans. EULE. — From half the sum of the three sides subtract each side separately; find the continued product of the half-sum and the three remainders; the square root of this product... | |
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RULE. from half the sum of the three sides, subtract each side separately; multiply the half sum and the three remainders together, and the square root of the product will be the area required. 
