Divide the number thus formed, omitting the last figure, by twice the part of the root already obtained, and annex the result to the root and also to the divisor. Then multiply the divisor, as it now stands, by the part of the root last obtained, and... The Elements of Algebra ... - Page 60by James Wood - 1825 - 305 pagesFull view - About this book
| Isaac Todhunter - Algebra - 1866 - 580 pages
...period. Divide this quantity, omitting the last figure, by twice the part of the root already found, and annex the result to the root and also to the divisor,...to be brought down the operation must be repeated. 242. Extract the square root of 6 1 1524 ; also of 10246401. 611524(^782 1024640Ц3201 49 9 l 48J1... | |
| William Harding Girdlestone - 1867 - 368 pages
...multiply the divisor as it now stands, and the required subtrahend will be obtained. If there should be more periods to be brought down, the operation must be repeated ; remembering to double only the last figure in the divisor at each successive step. Ex. 2. Find the... | |
| Daniel Barnard Hagar - Algebra - 1873 - 278 pages
...from the given polynomial. Divide the first term of the remainder by double the root already found, and annex the result to the root, and also to the divisor, for a complete divisor. Multiply the complete divisor by the second term of the root, and subtract... | |
| Isaac Todhunter - Algebra - 1876 - 350 pages
...period. Divide this quantity, omitting the last figure, by twice the part of the rout already found, and annex the result to the root and also to the divisor;...subtrahend. If there be more periods to be brought down, tlie operation must be repeated. 302. Examples. Extract the square root of 132496, and of 5322249.... | |
| Barnard Smith, Archibald McMurchy - Arithmetic - 1879 - 200 pages
...period, and to the remainder bring down, on the right, the second period. Divide the number thus formed, omitting the last figure, by twice the part of the...now stands, by the part of the root last obtained, and subtract the product from the number formed, as above mentioned, by the first remainder and second... | |
| Benjamin Greenleaf - Algebra - 1879 - 350 pages
...double the rt of the root already found, and annex the result to the root, and also to the divisor. Multiply the divisor as it now stands by the part of the root last obtained, and subtract the product from the dividend. If there are more periods to be brouj/d down, continue... | |
| Benjamin Greenleaf - 1879 - 346 pages
...by double tkt of the root already found, and annex the result to tht root, and also to t/ie divisor. Multiply the divisor as it now stands by the part of the roc: last obtained, and subtract the product from the dividend. If there are more periods to be brought... | |
| Benjamin Greenleaf - Algebra - 1879 - 322 pages
...given polynomial. Divide the first term of the remainder by double the part of the root already found, and annex the result to the root, and also to the divisor. Multiply the divisor as it now stands by the term of the root last obtained, and subtract the product... | |
| Webster Wells - Algebra - 1879 - 468 pages
...period for a dividend. Divide this dividend, omitting the last figure, by double the root already found, and annex the result to the root and also to the divisor. Multiply the divisor, as it now stands, by the figure of the root last obtained, and subtract the product... | |
| Benjamin Greenleaf - Algebra - 1879 - 350 pages
...root already fonnd, and annex the result to the root, and also to the divisor. Multiply the dii-isor as it now stands by the part of the root last obtained, and subtract the product from the dividend. If there are more periods to be bronght down, continue... | |
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