Prove that the area of an inscribed regular hexagon is a mean proportional between the areas of the inscribed and the circumscribed equilateral triangles. Plane Geometry - Page 243by Edward Rutledge Robbins - 1906 - 254 pagesFull view - About this book
| Education - 1906 - 592 pages
...one equilateral triangle is equal to the altitude of another, what is the rati of their areas ? 7. **The area of Ťan inscribed regular hexagon is a mean...proportional between •the areas of the inscribed and** circumscribed regular triangles. 8. With the vertices of a triangle as centers, describe three circles,... | |
| William Weller Strader, Lawrence D. Rhoads - Geometry, Plane - 1927 - 434 pages
...GH. Prove OC : OB = OH : OG. 25. Show that the area of a regular hexagon inscribed in a circle is the **mean proportional between the areas of the inscribed and the circumscribed equilateral triangles.** 26. One base of a trapezoid is 10 in., the altitude is 4 in. and the area is 32 sq. in. Find the length... | |
| William Betz, Harrison Emmett Webb, Percey Franklyn Smith - Geometry, Modern - 1912 - 356 pages
...area of the circumscribed equilateral triangle. 9. The area of the regular inscribed hexagon is the **mean proportional between the areas of the inscribed and the circumscribed equilateral triangles.** 10. In Ex. 6 compare the area of the given hexagon with that of any one of the figures pointed out.... | |
| Webster Wells - Geometry - 1887 - 144 pages
...A = 3 R2 л/3. But, f Д2л/ЗхЗ.КЧ/3==^.К1 = (| #V3)2. .-. the area of the regular inscribed **hexagon is a mean proportional between the areas of the inscribed and** circumscribed equilateral A. 9. From proof of Prop. VIII. , Z OEM = Z BOM = 36°. Then in the О described... | |
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