 Prove that the area of an inscribed regular hexagon is a mean proportional between the areas of the inscribed and the circumscribed equilateral triangles.  Plane Geometry - Page 243by Edward Rutledge Robbins - 1906 - 254 pagesFull view - About this book
 | Education - 1906 - 592 pages
...one equilateral triangle is equal to the altitude of another, what is the rati of their areas ? 7. The area of Ťan inscribed regular hexagon is a mean...proportional between •the areas of the inscribed and circumscribed regular triangles. 8. With the vertices of a triangle as centers, describe three circles,... | |
 | William Weller Strader, Lawrence D. Rhoads - Geometry, Plane - 1927 - 434 pages
...GH. Prove OC : OB = OH : OG. 25. Show that the area of a regular hexagon inscribed in a circle is the mean proportional between the areas of the inscribed and the circumscribed equilateral triangles. 26. One base of a trapezoid is 10 in., the altitude is 4 in. and the area is 32 sq. in. Find the length... | |
 | William Betz, Harrison Emmett Webb, Percey Franklyn Smith - Geometry, Modern - 1912 - 356 pages
...area of the circumscribed equilateral triangle. 9. The area of the regular inscribed hexagon is the mean proportional between the areas of the inscribed and the circumscribed equilateral triangles. 10. In Ex. 6 compare the area of the given hexagon with that of any one of the figures pointed out.... | |
 | Webster Wells - Geometry - 1887 - 144 pages
...A = 3 R2 л/3. But, f Д2л/ЗхЗ.КЧ/3==^.К1 = (| #V3)2. .-. the area of the regular inscribed hexagon is a mean proportional between the areas of the inscribed and circumscribed equilateral A. 9. From proof of Prop. VIII. , Z OEM = Z BOM = 36°. Then in the О described... | |
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