Multiply the divisor, thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 5. Double the whole root already found for a new divisor, and continue the... Academic Algebra - Page 274by George Wentworth, David Eugene Smith - 1913 - 458 pagesFull view - About this book
| William Guy Peck - Algebra - 1875 - 348 pages
...product to the trial divisor for a complete divisor. IV. Multiply the divisor thus completed by the trial figure of the root, subtract the product from the dividend, and to the remainder annex the -following period for a new dividend. V. Proceed as before, continuing the operation till all the periods... | |
| Horatio Nelson Robinson - Arithmetic - 1875 - 462 pages
...to the trial divisor for a complete divisor ; multiply the complete divisor by the trial figure in the root, subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. V. Multiply the last figure of the last complete divisor... | |
| Milton Browning Goff - Arithmetic - 1876 - 462 pages
...root ; 2d. The square of the last figure of the root. Multiply the divisor thus increased by the last figure of the root; subtract the product from the...remainder annex the next period for a new dividend. Form, in the same manner, successive divisors, and find corresponding figures of the root ; being careful... | |
| Edward Brooks - Arithmetic - 1876 - 588 pages
...the root ; their sum will be the COMPLETE DIVISOR. V. Multiply the COMPLETE DIVISOR by the last term of the root ; subtract the product from the dividend,...remainder annex the next period for a new dividend. Take 3 times the square of the root now found, regarded as tens, for a trial divisor, and find the... | |
| William Frothingham Bradbury - Algebra - 1877 - 302 pages
...right of the trial divisor for the TRUE DIVISOR. Multiply the true divisor by this new root figure, subtract the product from the dividend, and to the...remainder annex the next period, for a new dividend. NOTE 1. — When a root figure is 0, annex 0 also to,the trial divisor, and bring down the next period... | |
| William Frothingham Bradbury - Algebra - 1877 - 280 pages
...trial divisor, and the SUM will be the TRUE DIVISOR. Multiply the true divisor by the last root figure, subtract the product from the dividend, and to the remainder annex the next period for a dividend. Find a new trial divisor, and proceed as before, until all the periods have been employed.... | |
| William Guy Peck - Arithmetic - 1877 - 430 pages
...product to the trial divisor for a complete divisor. IV. Multiply the divisor thus completed by the trial -figure of the root, subtract the product from the dividend, and to the remainder annex the following period for a new dividend. V. Proceed as before, continuing the operation till all the periods... | |
| William James Milne - Arithmetic - 1877 - 402 pages
...complete divisor, the figure last found, multiply this divisor by the last figure of the root found, subtract the product from the dividend, and to the remainder annex the next period for the next dividend. Proceed in this manner until all the periods have been used thus. The result will... | |
| Joseph Ray - Arithmetic - 1877 - 402 pages
...and also on the right of the trial divisor. P«c. •» 4. Multiply the complete divisor by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 5. Double the whole root found, for a new trial divisor,... | |
| Albert Newton Raub - Arithmetic - 1877 - 348 pages
...Put this figure of the root in place of the cipher, and then multiply the entire divisor by this last figure of the root; subtract the product from the dividend, and to the difference annex the next period for a new dividend. 6. Double the root already found, with a cipher... | |
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