| Horatio Nelson Robinson - History - 1853 - 334 pages
...If a perpendicular be let fall from any angle of a triangle to its opposite side or base, this base is to the sum of the other two sides, as the difference of the sides is to the difference of the segments of the base. (See figure to proposition 5.) Let AB be the base, and from (7, as a center,... | |
| Elias Loomis - Trigonometry - 1855 - 192 pages
...any angle of a triangle a perpendicular be drawn to the opposite side or base, the whole base will be to the sum of the other two sides, as the difference of those two sides is to the difference of the segments of the base. For demonstration, see Geometry,... | |
| George Roberts Perkins - Geometry - 1856 - 460 pages
...triangle a perpendicular be drawn so as to meet the opposite side or "base^ the whole lose will be to the sum of the other two sides as the difference of those sides is to the difference of the segments of the lose. Drawing CD perpendicular to AB, we have... | |
| Horatio Nelson Robinson - Navigation - 1858 - 356 pages
...If a perpendicular be let fall from any angle of a triangle to Us opposite side or base, this lose is to the sum of the other two sides, as the difference of the sides is to the di/erence of the segments of the base. (See figure to proposition 5.) Let AB be the base, and from... | |
| Elias Loomis - Logarithms - 1859 - 372 pages
...any angle of a triangle a perpendicular be drawn to the opposite side or base, the whole base will be to the sum of the other two sides, as the difference of those two sides is to the difference of the segments of the base. For demonstration, see Geometry,... | |
| Horatio Nelson Robinson - Geometry - 1860 - 470 pages
...If a perpendicular be let fall from any angle of a triangle to its opposite side or base, 'this base is to the sum of the other two sides, as the difference of the sides is to the difference of the segments of the base. (See figure to Proposition 5.) It is obvious that AE is the sum of the... | |
| George Roberts Perkins - Geometry - 1860 - 472 pages
...triangle a perpendicular 1)0 drawn so as to meet the opposite side or base, the whole base will be to the sum of the other two sides as the difference of those sides is to the difference of the segments of the base. Drawing CD perpendicular to AB, we have... | |
| Horatio Nelson Robinson - Conic sections - 1862 - 356 pages
...because PGr is drawn perpendicular to the base of the triangle F'PF, the base is to the sum of the two sides, as the difference of the sides is to the difference of the segments of the base, (Prop. 6, PL Trig.) Whence, F'F: F'P+PF: :F'P—PF: 2CG (2) If we multiply... | |
| Evan Wilhelm Evans - Geometry - 1862 - 116 pages
...perpendicular be let fall from the vertex of a triangle upon its base, the sum of the parts of the base is to the sum of the other two sides as the difference of the latter is to the difference of the former. Proof. Let BD be the perpendicular. Now, BC2— CD2= BD2... | |
| Horatio Nelson Robinson - Conic sections - 1863 - 362 pages
...Again, because PG is drawn perpendicular to the base of the triangle F'PF, the base is to the sum of the two sides, as the difference of the sides is to the difference of the segments of the base, (Prop. 6, PL Trig.) Whence, F'F: F'P+PF: : F'P—PF: 2 CG (2) If we multiply... | |
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