 | 268 pages
...constant. .: locus of A is a circle whose centre is the mid. pt. of BC. 1 61 , 3. The sum of the squares on the sides of a parallelogram is equal to the sum of the squares on the diagonals. Let ABCD be a grain, whose diagonals bisect each other at O (91,1). Now sqs... | |
 | James McMahon - 2018 - 244 pages
...its locus is a circle, having for centre the mid-point of AB. tEx. 1142. The sum of the squares on the sides of a parallelogram is equal to the sum of the squares on the diagonals. tEx. 1143. In any quadrilateral the sum of the squares on the four sides... | |
 | Mathematics - 1965 - 232 pages
...that BC = CP. Given that AB = AC = 2BC, show that AP* = 6BC*. 2. Prove that the sum of the squares on the sides of a parallelogram is equal to the sum of the squares on the diagonals. 3. APQ is a triangle and PQ is produced to B and C so that BP=PQ= QC. Prove... | |
 | Newfoundland Council of Higher Education - 1919 - 180 pages
...having each of the base angles double of the vertical angle. 4. Prove that the sum of the squares on the sides of a parallelogram is equal to the sum of the squares on the diagonals. 5. If the base and vertical angle of a triangle are given, prove the locus... | |
 | G. P. West - Geometry - 1965 - 362 pages
...its locus is a circle having for centre the mid-point of AB. 13. Prove that the sum of the squares on the sides of a parallelogram is equal to the sum of the squares on the diagonals. 14. Show that, if AX, BY are medians of AABC, AX2 - BY2 = | (AC2 - BC2).... | |
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The sum of the squares on the sides of a parallelogram is equal to the sum of the squares on the diagonals. 
