RULE. from half the sum of the three sides, subtract each side separately; multiply the half sum and the three remainders together, and the square root of the product will be the area required. Higher Book - Page 252by William Seneca Sutton - 1896Full view - About this book
| Edward Richard Shaw - 1887 - 488 pages
...* = 244. That which has length and breadth only. 245. Multiply the base by half the altitude. 246. **From half the sum of the three sides subtract each side separately,** multiply the half sum and the three remainders together, and extract the square root of the product.... | |
| Charles Scott Venable - Arithmetic - 1888 - 402 pages
...equals half of the product of either side by the perpendicular to it from the opposite vertex; or, **from half the sum of the three sides subtract each side separately** ; multiply together the half sum and the three remainders ; and the square root of the product is the... | |
| Andrew Jackson Rickoff - 1888 - 470 pages
...following rule is sometimes necessary : When the three sides of a triangle are given, to find the area: **From half the sum of the three sides subtract each side separately.** Multiply the half sum and the three remainders together, and extract the square root of the product.... | |
| Thomas A. Rice - Accounting - 1889 - 364 pages
...Multiply three sides together. 6. To find area of triangle. — Multiply base by half the altitude. Or, **from half the sum of the three sides subtract each side separately** ; multiply the half sum by the three remainders, and extract square root of product. 7. To find area... | |
| Horatio Nelson Robinson - Arithmetic - 1892 - 430 pages
...= 60 ; 60 - 30 = 30 ; 60 - 40 = 20; 60 - 50 = 10. \X60~x30 x 20 x 10 = 600 sq. ft., area. RULE. — **From half the sum of the three sides subtract each side separately;** multiply the half-sum and the three remainders together; the square root of the product is the area.... | |
| Horatio Nelson Robinson - Arithmetic - 1892 - 428 pages
...2 = 60 ; 60 - 30 = 30 ; 60 - 40 = 20 ; 60 - 50 = 10. V60x30x20xlo' = 600 sq. ft. , area. RULE. — **From half the sum of the three sides subtract each side separately** ; multiply the half-sum and the three remainders together; the square root of the product is the area.... | |
| Massachusetts - Massachusetts - 1893 - 986 pages
...product of the side and perpendicular, and divide by 160. (ft) When three sides are given. Rule. — **From half the sum of the three sides subtract each side separately** ; multiply the half sum and the three remainders together; the square root of the product divided by... | |
| Horatio Nelson Robinson - Arithmetic - 1895 - 526 pages
...= GO ; CO - 30 = 30 ; 60 - 40 = 20 ; 60 - 50 = 10. V60 x 30 x 20 x 10 = 600 ft, area Ans. EULE. — **From half the sum of the three sides subtract each side separately; find the** continued product of the half-sum and the three remainders; the square root of this product is the... | |
| William Frothingham Bradbury - Arithmetic - 1895 - 398 pages
...yards and the altitude 15 yards. What is the area t 463. To find the area of a triangle when only the **three sides are given, From half the sum of the three sides subtract** successively the three sides ; find the square root of the product of these three remainders and the... | |
| George Washington Hull - Arithmetic - 1895 - 396 pages
...if the three sides of a triangle are given and not the altitude, the area can be found as follows : **From half the sum of the three sides subtract each side separately** ; multiply the half sum and the three remainders together, and extract the square root of the product... | |
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