RULE. from half the sum of the three sides, subtract each side separately; multiply the half sum and the three remainders together, and the square root of the product will be the area required. Higher Book - Page 252by William Seneca Sutton - 1896Full view - About this book
| Henry Lewis (M.A.) - Measurement - 1875 - 104 pages
...The area of a triangle may, however, be determined from its three sides by the following rule: — **From half the sum of the three sides, subtract each side separately;** then multiply the half sum and the three remainders together, and the square root of the last product... | |
| Malcolm MacVicar - Arithmetic - 1876 - 412 pages
...the rafters ? 801. PROB. III. — When the three sides of a triangle are given, to find the area : **From half the sum of the three sides subtract each side separately.** Multiply the half sum and the three remainders together ; the square root of the product is the area.... | |
| Popular encyclopedia - 1877 - 536 pages
...half the perpendicular from the vertex. Area of a triangle when the lengths of the sides are known; **from half the sum of the three sides subtract each side separately;** multiply the half sum and the three remainders together, and extract the square-root of the product.... | |
| Stoddard A. Felter, Samuel Ashbel Farrand - Arithmetic - 1877 - 496 pages
...remainder. 27 — 24 = 3, 3d remainder. 27 X 15 X 9 X 3 = 10935. y 10935 = 104.57 sq. rds. area. RULE. — **From half the sum of the three sides subtract each side separately** ; then multiply the continued product of these remainders by half the sum of the sides, and extract... | |
| William James Milne - Arithmetic - 1877 - 402 pages
...product of the base by the altitude. When the three sides are given, the following is the rule: RULE. — **From half the sum of the three sides subtract each side separately.** Multiply together the half sum and the three remainders, and extract the square root of the product.... | |
| Samuel Mecutchen, George Mornton Sayre - Arithmetic - 1877 - 200 pages
...right triangle, AB is the hypotenuse, and AC, the perpendicular. To find the area of a triangle. RULE. **from half the sum of the three sides, subtract each side separately;** multiply the half sum and the three remainders together, and the square root of the product will be... | |
| John Barter (of the science and art coll, Plymouth.) - 1877 - 328 pages
...completed ? EXERCISE CCXV. Having the three sides of any triangle given, to find its area. Rule. — **From half the sum of the three sides subtract each side separately,** multiply the half sum and the three remainders together, and the square root of the last product will... | |
| Alfred Hiley - 1879 - 230 pages
...given. Multiply the base by the height, and divide the product by 2. (2) To find the area, when the **three sides are given. From half the sum of the three sides, subtract each side separately.** Multiply the half sum and the three remainders together, and the square root of the product is the... | |
| Edward Olney - Arithmetic - 1879 - 392 pages
...base and altitude, or half of either multiplied into the oiher. 446. NOTE. — If the three sides only **are given, from half the sum of the three sides subtract each side separately,** multiply Hie half sum and these remainders together, and extract the square root of the product. The... | |
| William Frothingham Bradbury - Arithmetic - 1879 - 392 pages
...meters and the altitude 15 meters; what is the area? 463. To find the area of a triangle when only the **three sides are given, From half the sum of the three sides subtract** successively the three sides ; find the square root of the product of these three remainders and the... | |
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