 RULE. from half the sum of the three sides, subtract each side separately; multiply the half sum and the three remainders together, and the square root of the product will be the area required.  Higher Book - Page 252by William Seneca Sutton - 1896Full view - About this book
 | Henry Lewis (M.A.) - Measurement - 1875 - 104 pages
...The area of a triangle may, however, be determined from its three sides by the following rule: — From half the sum of the three sides, subtract each side separately; then multiply the half sum and the three remainders together, and the square root of the last product... | |
 | Malcolm MacVicar - Arithmetic - 1876 - 412 pages
...the rafters ? 801. PROB. III. — When the three sides of a triangle are given, to find the area : From half the sum of the three sides subtract each side separately. Multiply the half sum and the three remainders together ; the square root of the product is the area.... | |
 | Popular encyclopedia - 1877 - 536 pages
...half the perpendicular from the vertex. Area of a triangle when the lengths of the sides are known; from half the sum of the three sides subtract each side separately; multiply the half sum and the three remainders together, and extract the square-root of the product.... | |
 | Stoddard A. Felter, Samuel Ashbel Farrand - Arithmetic - 1877 - 496 pages
...remainder. 27 — 24 = 3, 3d remainder. 27 X 15 X 9 X 3 = 10935. y 10935 = 104.57 sq. rds. area. RULE. — From half the sum of the three sides subtract each side separately ; then multiply the continued product of these remainders by half the sum of the sides, and extract... | |
 | William James Milne - Arithmetic - 1877 - 402 pages
...product of the base by the altitude. When the three sides are given, the following is the rule: RULE. — From half the sum of the three sides subtract each side separately. Multiply together the half sum and the three remainders, and extract the square root of the product.... | |
 | Samuel Mecutchen, George Mornton Sayre - Arithmetic - 1877 - 200 pages
...right triangle, AB is the hypotenuse, and AC, the perpendicular. To find the area of a triangle. RULE. from half the sum of the three sides, subtract each side separately; multiply the half sum and the three remainders together, and the square root of the product will be... | |
 | John Barter (of the science and art coll, Plymouth.) - 1877 - 328 pages
...completed ? EXERCISE CCXV. Having the three sides of any triangle given, to find its area. Rule. — From half the sum of the three sides subtract each side separately, multiply the half sum and the three remainders together, and the square root of the last product will... | |
 | Alfred Hiley - 1879 - 230 pages
...given. Multiply the base by the height, and divide the product by 2. (2) To find the area, when the three sides are given. From half the sum of the three sides, subtract each side separately. Multiply the half sum and the three remainders together, and the square root of the product is the... | |
 | Edward Olney - Arithmetic - 1879 - 392 pages
...base and altitude, or half of either multiplied into the oiher. 446. NOTE. — If the three sides only are given, from half the sum of the three sides subtract each side separately, multiply Hie half sum and these remainders together, and extract the square root of the product. The... | |
 | William Frothingham Bradbury - Arithmetic - 1879 - 392 pages
...meters and the altitude 15 meters; what is the area? 463. To find the area of a triangle when only the three sides are given, From half the sum of the three sides subtract successively the three sides ; find the square root of the product of these three remainders and the... | |
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