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" RULE. from half the sum of the three sides, subtract each side separately; multiply the half sum and the three remainders together, and the square root of the product will be the area required. "
Higher Book - Page 252
by William Seneca Sutton - 1896
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Stoddard's Complete Arithmetic: Being the New Practical Arithmetic of the ...

John Fair Stoddard - Arithmetic - 1888 - 480 pages
...ft triangle. Rule. — Multiply its base by half its altitude. NOTE. — If the three sides, only, are given, From half the sum of the three sides, subtract each side separately, multiply the half sum and these remainders together, und extract the square root of the product. 1....
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Practical Arithmetic, Embracing the Science of Numbers and the Art of ...

John Fair Stoddard - Arithmetic - 1868 - 430 pages
...of a triangle. Rule. — Multiply its base by half Us altitude. NOTE. — If the three sides, only, are given, From half the sum of the three sides, subtract each sidt teparately, multiply the half sum and these remainders together, ind extract the square root of...
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The Crittenden Commercial Arithmetic and Business Manual: Designed for the ...

John Groesbeck - Arithmetic - 1868 - 350 pages
...length by the breadth. To find the area of a triangle. Multiply the base by one-half the altitude. Or, From half the sum of the three sides subtract each side separately ; multiply together the half sum and the three remainders, and extract the square root of the product....
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Mensuration for Beginners: With Numerous Examples

Isaac Todhunter - Measurement - 1869 - 312 pages
...the quotient is the height. 152. The three sides of a triangle being given, to find the area. RULE. From half the sum of the three sides subtract each side separately ; multiply the half sum and the three remainders together : the square root of the product witt be...
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Crittenden Commercial Arithmetic ...

John Groesbeck - 1872 - 374 pages
...length by the breadth. To find the area of a triangle. Multiply the base by one-half the altitude. Or, From half the sum of the three sides subtract each side separately ; multiply together the half sum and the three remainders, and extract the tquare root of the product....
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New Elementary Geometry: With Practical Applications ; a Shorter Course Upon ...

Benjamin Greenleaf - Geometry - 1873 - 202 pages
...altitude are given, multiply the base by half the altitude, or half the base by the altitude. If the three sides are given, from half the sum of the three sides subtract each side ; multiply the half sum and the three remainders together, and the square root of the product will...
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Plane and spherical trigonometry. [With] Solutions of problems. [Followed by ...

Henry William Jeans - 1873 - 288 pages
...area. Ans. 80627 square yards. RULE VII. Three sides of a plane triangle being given, to find the area. From half the sum of the three sides, subtract each side separately. Add together the log. of the half sum and the logarithms of the three remainders. Half the result will...
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New Elementary Geometry: With Practical Applications : a Shorter Course Upon ...

Benjamin Greenleaf - Geometry - 1874 - 206 pages
...altitude are given, multiply the base by half the altitude, or half the base by the altitude. If the three sides are given, from, half the sum of the three sides subtract each side ; multiply the half sum and the three remainders together, and the square root of the product will...
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The Complete Arithmetic: Oral and Written

Daniel W. Fish - Arithmetic - 1874 - 524 pages
...area of an isosceles triangle whose base is 20 ft., and each of its equal sides 15 feet ? RULE. — From half the sum of the three sides, subtract each side separately; multiply the half -sum and the three remainders together; the square root of the product is the area....
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A Practical Business Arithmetic ...

Lorenzo Fairbanks - 1875 - 468 pages
...18.25 chains ? PROBLEM III. 710. To find the area of a triangle when three sides are given. RULE. — From half the sum of the three sides subtract each side separately. Then multiply the half sum and the three remainders continually together, and the square root of the...
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