RULE. from half the sum of the three sides, subtract each side separately; multiply the half sum and the three remainders together, and the square root of the product will be the area required. Higher Book - Page 252by William Seneca Sutton - 1896Full view - About this book
| Alfred Newsom Niblett - 1861 - 204 pages
...the base by the perpendicular, and half the product will be the area. CASE 2.—The three sides being **given. From half the sum of the three sides subtract each side separately,** multiply the half sum and the three remainders continually together, and the square root of the last... | |
| Janes Boddely Keene - 1861 - 104 pages
...area in square yards ? Ans. 875 one-9th yds. When the Three Sides of a Triangle are given. RULE. — **From half the sum of the three sides subtract each side separately** ; then multiply the half sum and the three remainders together, and the square root of the last product... | |
| Daniel Adams - Arithmetic - 1861 - 454 pages
...point at the other ? Ans. 131 feet. To find the area of a triangle when the length of each side is **given, — From half the sum of the three sides subtract each side** severally ; then multiply the half sum and the three remainders continually together, and the square... | |
| Benjamin Greenleaf - Geometry - 1862 - 514 pages
...angle 40 rods ? Ans. 12 A. 20 P. PROBLEM IX. 622. To find the area of a TRIANGLE, the three sides being **given. From half the sum of the three sides subtract each side** ; multiply the half sum and the three remainders together, and the square root of the product will... | |
| Oliver Byrne - Engineering - 1863 - 600 pages
...= 38 fe. 11 in. A " " 7J pa. = area required. To find the area of a triangle whose three sides only **are given. — From half the sum of the three sides subtract each side** severally. Multiply the half sum and the three remainders continually together, and the square root... | |
| Stoddard A. Felter - Arithmetic - 1864 - 412 pages
...8ft. X 2 = 16 sq.ft. PROB. II. — The sides of a triangle being given to find the area. RULE. — **From half the sum of the three sides subtract each side separately,** then multiply the continued product of these remainders by half the sum of the sides, and extract the... | |
| Benjamin Greenleaf - Geometry - 1866 - 328 pages
...angle 40 rods ? Ans. 12 A. 20 P. PROBLEM IX. 622. To find the area of a TRIANGLE, the three sides being **given. From half the sum of the three sides subtract each side** ; multiply the half sum and the three remainders together, and the square root of the product will... | |
| Whiting Griswold - Railroad engineering - 1866 - 144 pages
...angle, and one-half the product equals the area. To find the area of a triangle by its sides. RULE 8. **From half the sum of the three sides subtract each side separately** ; then multiply the half sum and the three remainders continually together, and the square root of... | |
| Edward Thomas Stevens - 1866 - 434 pages
...hypoteneuse required. To Jind the area of any triaiu]k when the three sides only are gicen. KULE : — **From half the sum of the three sides subtract each side separately,** then multiply the half sum and the three remainders together. The square root of the product is the... | |
| John Groesbeck - Arithmetic - 1867 - 226 pages
...length by the breadth. To find the area of a triangle. Multiply the base by one-half the altitude. Or, **From half the sum of the three sides subtract each side separately** ; multiply together the half sum and the three remainders, and extract the square root of the product.... | |
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