RULE. from half the sum of the three sides, subtract each side separately; multiply the half sum and the three remainders together, and the square root of the product will be the area required. Higher Book - Page 252by William Seneca Sutton - 1896Full view - About this book
| 1908 - 560 pages
...Scale, 10 chains to 1 inch. xvy.-? The area of the resulting triangle may be found as follows : — **From half the sum of the three sides subtract each side separately;** multiply the half sum and the three remainders together; the square root of the product will be the... | |
| Gustavus Sylvester Kimball - Business mathematics - 1911 - 444 pages
...Solution. (20+30+40) -5-2 =45; 45-20 = 25; 45-30 = 15; 45-40 = 5. ^45X25X15X5 = 290.4 + ft. 357. Rule. **From half the sum of the three sides, subtract each side separately.** Multiply the half sum and the three remainders together, and extract the square root of the product.... | |
| George Morris Philips, Robert Franklin Anderson - Arithmetic - 1913 - 444 pages
..."" ~~2~• 405. To find the area of a triangle when its three sides are given, apply the following : **From half the sum of the three sides, subtract each side separately;** multiply together the number of units in the half sum and in each of the three remainders, and extract... | |
| Joseph Gregory Horner - Iron-founding - 1914 - 460 pages
...breadth. 2. Triangle. Multiply the base by the perpendicular height, and take half the product. Or: **From half the sum of the three sides subtract each side separately,** multiply the half sum and the three remainders together; the square root of the product will be the... | |
| Harry Anson Finney, Joseph Clifton Brown - Business mathematics - 1916 - 506 pages
...= 2. 24 x 12 x 10 x 2 = 5760. V5760 = 75.88, the number of square feet in the area. Rule. From one **half the sum of the three sides subtract each side separately. Find the** product of the half sum and of the three remainders. Extract the square root of this product. The result... | |
| United States - 1918 - 840 pages
..."perpendicular to it from the opposite vertex equals the area. Formula: — ^-£=area. (Fig. 6, page 51.) Or **from half the sum of the three sides subtract each side separately,** multiply together the half sum and the three remainders, the square root of the product is the area.... | |
| Hugh Findlay - Agriculture - 1920 - 584 pages
...take one-half the product of the side and perpendicular, and divide by one hundred and sixty. When **three sides are given, from half the sum of the three sides subtract each side separately;** multiply the half sum and the three remainders together; the square root of the product divided by... | |
| Hugh Findlay - Agriculture - 1920 - 586 pages
...take one-half the product of the side and perpendicular, and divide by one hundred and sixty. When **three sides are given, from half the sum of the three sides subtract each side separately;** multiply the half sum and the three remainders together; the square root of the product divided by... | |
| Joseph Gregory Horner - 1920 - 418 pages
...dimensions are given in terms of the length of the three sides, then the area is found as follows :— **From half the sum of the three sides, subtract each side separately.** Multiply the half sum and the three remainders together, the square root of the product will be the... | |
| Adolf Hopp, William Neubecker - Sheet-metal work - 1921 - 436 pages
...the dimensions of the three sides are known or can be obtained. The rule in this case is as follows : **From half the sum of the three sides subtract each side separately; find the** continued product of the half sum of the sides and the three remainders, and the square root of this... | |
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