RULE. from half the sum of the three sides, subtract each side separately; multiply the half sum and the three remainders together, and the square root of the product will be the area required. Higher Book - Page 252by William Seneca Sutton - 1896Full view - About this book
| John Hind - Arithmetic - 1840 - 252 pages
...Triangle. The area is equal to half the product of the base and the perpendicular altitude. (3) Triangle. **From half the sum of the three sides, subtract each side separately:** multiply together the half-sum and the three remainders, and the square root of the product will be... | |
| Henry W. Jeans - Trigonometry - 1842 - 138 pages
....-.2 area. . 300832 and area 150416 VI. Three sides of a plane triangle being given, to find the area. **From half the sum of the three sides, subtract each side separately.** Add together, the log. of the hah0 sum, and the logarithms of the three remainders. Half the result... | |
| Charles WATERHOUSE - Arithmetic - 1844 - 228 pages
...ft. X 12 ft.=192 ft., Ans. „ 3. To find the area of a triangle. RULE. — If the three sides only **are given. — From half the sum of the three sides, subtract each side** severally ; multiply these three remainders and the said half sum continually together ; and the square... | |
| Charles Haynes Haswell - Engineering - 1844 - 264 pages
...the product will be the area. To find the Area of a Triangle by the length of its sides. RULE. — **From half the sum of the three sides subtract each side separately** ; then multiply the half sum and the \hree remainders continually together, and the square root of... | |
| 458 pages
...sq. ft. 11 parts, 7*in.; each part being l-12thofasq. ft., that is, equal to 12 sq. in. PROBLEM III. **To find the area of a triangle, whose three sides...half the sum of the three sides subtract each side** severally, then multiply the half sum and the three remainders continually together, and the square... | |
| James Bates Thomson - Arithmetic - 1847 - 424 pages
...perpendicular height. 390 MENSURATION. [SECT. XIX. 626. To find the area of a triangle, the three sides being **given. From half the sum of the three sides subtract each side** respectively ; then multiply together half the sum and the three remainders, and extract the square... | |
| James Bates Thomson - Arithmetic - 1847 - 432 pages
...the altitude or perpendicular height. (>2(». To find the area of a triangle, the three sides being **given. From half the sum of the three sides subtract each side** respectively ; then multiply together half the sum and the three remainders, and extract the square... | |
| William Templeton (engineer.) - 1848 - 258 pages
...base by a perpendicular let fall from the opposite angle, and take half the product for the area. Or, **from half the sum of the three sides subtract each side separately,** and multiply the three remainders so obtained and the half sum together, and the square root of the... | |
| Oliver Byrne - Engineering - 1851 - 310 pages
...38 fe. 11 in. A " " 7 J pa. = area required. To find the area of a triangle whose three sides only **are given. — From half the sum of the three sides subtract each side** severally. Multiply the half sum and the three remainders continually together, and the square root... | |
| Daniel Leach - Arithmetic - 1851 - 280 pages
...yards ? 364. To find the area of a triangle, when the length of its three sides is known,— RULE. **From half the sum of the three sides subtract each side separately.** Then multiply the half sum by each side in succession. The square root of the continued product will... | |
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