 RULE. from half the sum of the three sides, subtract each side separately; multiply the half sum and the three remainders together, and the square root of the product will be the area required.  Higher Book - Page 252by William Seneca Sutton - 1896Full view - About this book
 | John Hind - Arithmetic - 1840 - 252 pages
...Triangle. The area is equal to half the product of the base and the perpendicular altitude. (3) Triangle. From half the sum of the three sides, subtract each side separately: multiply together the half-sum and the three remainders, and the square root of the product will be... | |
 | Henry W. Jeans - Trigonometry - 1842 - 138 pages
....-.2 area. . 300832 and area 150416 VI. Three sides of a plane triangle being given, to find the area. From half the sum of the three sides, subtract each side separately. Add together, the log. of the hah0 sum, and the logarithms of the three remainders. Half the result... | |
 | Charles WATERHOUSE - Arithmetic - 1844 - 228 pages
...ft. X 12 ft.=192 ft., Ans. „ 3. To find the area of a triangle. RULE. — If the three sides only are given. — From half the sum of the three sides, subtract each side severally ; multiply these three remainders and the said half sum continually together ; and the square... | |
 | Charles Haynes Haswell - Engineering - 1844 - 264 pages
...the product will be the area. To find the Area of a Triangle by the length of its sides. RULE. — From half the sum of the three sides subtract each side separately ; then multiply the half sum and the \hree remainders continually together, and the square root of... | |
 | 458 pages
...sq. ft. 11 parts, 7*in.; each part being l-12thofasq. ft., that is, equal to 12 sq. in. PROBLEM III. To find the area of a triangle, whose three sides...half the sum of the three sides subtract each side severally, then multiply the half sum and the three remainders continually together, and the square... | |
 | James Bates Thomson - Arithmetic - 1847 - 424 pages
...perpendicular height. 390 MENSURATION. [SECT. XIX. 626. To find the area of a triangle, the three sides being given. From half the sum of the three sides subtract each side respectively ; then multiply together half the sum and the three remainders, and extract the square... | |
 | James Bates Thomson - Arithmetic - 1847 - 432 pages
...the altitude or perpendicular height. (>2(». To find the area of a triangle, the three sides being given. From half the sum of the three sides subtract each side respectively ; then multiply together half the sum and the three remainders, and extract the square... | |
 | William Templeton (engineer.) - 1848 - 258 pages
...base by a perpendicular let fall from the opposite angle, and take half the product for the area. Or, from half the sum of the three sides subtract each side separately, and multiply the three remainders so obtained and the half sum together, and the square root of the... | |
 | Oliver Byrne - Engineering - 1851 - 310 pages
...38 fe. 11 in. A " " 7 J pa. = area required. To find the area of a triangle whose three sides only are given. — From half the sum of the three sides subtract each side severally. Multiply the half sum and the three remainders continually together, and the square root... | |
 | Daniel Leach - Arithmetic - 1851 - 280 pages
...yards ? 364. To find the area of a triangle, when the length of its three sides is known,— RULE. From half the sum of the three sides subtract each side separately. Then multiply the half sum by each side in succession. The square root of the continued product will... | |
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