 | James Bates Thomson - Arithmetic - 1846 - 362 pages
...greatest cube in the left hand period, which in the example above is 8, the root of which is 2. We subtract this cube from the left hand period, and to the remainder bring down the next period, in order to find how many feet remain to be added. In making this addition, it is plain... | |
 | Davis Wasgatt Clark - Algebra - 1846 - 374 pages
...the root. 2. Find the first figure of the root by trial, and subtract its power from the left-hand period, and to the remainder bring down the first figure of the next period for a dividend. 3. Involve the root to the next inferior power to that which is given, and multiply... | |
 | Almon Ticknor - Arithmetic - 1846 - 276 pages
...hand period, and place <he root to the right of the given number, and subtract the cube of the root from the left hand period, and to the remainder bring down the next period for a dividend. 3. Square the root, and multiply it by three for a defective divisor. 4.... | |
 | Charles Davies - Arithmetic - 1847 - 368 pages
...the right after the manner of a quotient in division. Subtract the cube of this figure from the first period, and to the remainder bring down the first...the next period, and call this number the dividend. III. Take three times the square of the root just found for a divisor and see how often it is contained... | |
 | Charles Davies - Arithmetic - 1847 - 368 pages
...given number, diminish the last figure, but if it be less, subtract it from the first two periods, and to the remainder bring down the first figure of the next period, for a new dividend. IV. Take three times the square of the whole root for a new divisor, and seek how... | |
 | Charles Davies - Arithmetic - 1850 - 412 pages
...the right after the manner of a quotient in division. Subtract the cube of this figure from the first period, and to the remainder bring down the first...the next period, and call this number the dividend. III. Take three times the square of the root just found for a divisor and see how often it is contained... | |
 | James Bates Thomson - Arithmetic - 1850 - 352 pages
...greatest cube in the left hand period, which in the example above is 8, the root of which is 2. We subtract this cube from the left hand period, and to the remainder bring down the next period, in order to find how many feet remain to be added. In making this addition, it is plain... | |
 | Arithmetic - 1851 - 260 pages
...root. 2 Find the first figure of the root by the table of powers, or by trial ; subtract its power from the left hand period, and to the remainder bring down the first figure in the next period for a dividend. 3 Involve the root to the next inferior power to that which is given,... | |
 | Benjamin Peirce - Algebra - 1851 - 294 pages
...and its root is the left hand figure of the required root. Subtract the square of the root thus found from the left hand period, and to the remainder bring down the second period for a dividend. Double the root for a divisor, and the quotient of the dividend exclusive... | |
 | Charles Davies - 1852 - 344 pages
...given number, diminish the last figure, but if it be less, subtract it from the first two periods, and to the remainder bring down the first figure of the next period for a new dividend. IY. Take three times the square of the whole root for a second trial divisor, and... | |
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Subtract the cube of this number from the first period, and to the remainder bring down the first figure of the next period for a dividend. 
