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" Subtract the cube of this number from the first period, and to the remainder bring down the first figure of the next period for a dividend. "
Mathematical Dictionary and Cyclopedia of Mathematical Science: Comprising ... - Page 134
by Charles Davies, William Guy Peck - 1855 - 592 pages
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A New System of Arithmetick: In which the Rules are Familiarly Demonstrated ...

William Ruger - Arithmetic - 1832 - 282 pages
...so on. 2. Find the first figure of the root by the table of powers, or by trial; subtract its power from the left hand period, and to the remainder bring down the first figure in the next period for an imperfect dividend. 3. Involve the root to the next inferiour power to that...
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The Youth's Assistant in Theorhetic [sic] and Practical Arithmetic: Designed ...

Zadock Thompson - Arithmetic - 1832 - 182 pages
...each, find the greatest cuhe in the left hand period, and place its root in the quotient. Subtract the cube from the left hand period, and to the remainder bring down the next period for a dividend. Multiply the square of the quotient by 300, calling it the triple square,...
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The Youth's Assistant in Theoretic and Practical Arithmetic: Designed for ...

Zadock Thompson - Arithmetic - 1832 - 186 pages
...each, find the greatest cube in the left hand period, and place its root in the quotient. Subtract the cube from the left hand period, and to the remainder bring down the next period for a dividend. Multiply the square of the quotient by 300, calling it the triple square,...
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The Tutor's Assistant: Being a Compendium of Arithmetic and a Complete ...

Francis Walkingame - 1832 - 224 pages
...that number from as many points of the given power, as is brought down, beginning at the lower place, and to the remainder bring down the first figure of the next point for a new dividend. 7. Find a new divisor, and proceed in all rejpectt as before. EXAMPLES. 1....
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The Arithmetical Manual

Samuel Read Hall - Arithmetic - 1832 - 294 pages
...this will be the highest figure in the root required. Subtract the square of the root already found from the left hand period, and to the remainder bring down the next period for a dividend. Double the root already found for a divisor ; seek how many times the divisor...
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The Common School Arithmetic: Prepared for the Use of Academies and Common ...

Charles Davies - Arithmetic - 1833 - 284 pages
...the given number, diminish the last figure, but if it be less subtract it from the two first periods, and to the remainder bring down the first figure of the next period, for a new dividendTV. Take three times the square of the whole root far a new divisor, and seek how...
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The Tutor's Assistant: Being a Compendium of Practical Arithmetic, for the ...

Francis Walkingame - 1833 - 204 pages
...involve the whole root to the given power for a subtrahend, which subtract from the first two periods. 6. To the remainder bring down the first figure of the next period for a new dividend ; find a new divisor and a new sub* trahend as before ; subtract from three periods,...
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The North American Arithmetic: Part Third, for Advanced Scholars, Volume 3

Frederick Emerson - Arithmetic - 1834 - 300 pages
...square in the left hand period, and write its root in the quotient. Subtract the square of this root from the left hand period, and to the remainder bring- down the next period for a dividend. Thirdly — Double the root already found, for a divisor. Ascertain how...
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The Teachers' Assistant: Or a System of Practical Arithmetic

Stephen Pike - Arithmetic - 1835 - 210 pages
...contained in the left hand period, and set its root on the right of the given number: subtract said cube from the .left hand period, and to the remainder bring down the next period for a dividual. 3. Square the root and multiply the square by 3 for a defective divisor....
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The New System of Practical Arithmetic: Whereby Most of the Various Problems ...

Charles Potts - Arithmetic - 1835 - 202 pages
...greatest cube in the left hand period, and set its root on the right of the given number ; subtract said cube from the left hand period, and to the remainder bring down the next period for a dividual. 3. Square the root, and multiply the square by 3 for a defective divisor....
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