 | Thomas William Silloway - Carpentry - 1858 - 236 pages
...and the product will be the area. PROBLEM II. TO FIND THE AREA OF A TRIANGLE. RULE. — Multiply tlie base by the perpendicular height, and half the product will be the area. PROBLEM III. TO FIND THE AREA OF A TRIANGLE WHOSE THREE SIDES ABE GIVEN. RULE. — From the half-sum... | |
 | Frederick Augustus Griffiths - Artillery - 1859 - 426 pages
....1 .r 4 .'> (1 7V EB To find the area of a triangle, its base, and perpendicular height being given. Multiply the base by the perpendicular height, and half the product will be the area. Example. — Required the number of square yards contained in a triangle, whose base is 20 yards, and perpendicular... | |
 | Rāmachandra (son of Sundara Lāla.) - Maxima and minima - 1859 - 250 pages
....-. - Z. - = i equation to the Sphere. (5.) TO FIND THE AREA OF A TKIANGLE. (Fig. 4.) Rule 1st. — Multiply the base by the perpendicular height, and half the product will be the area. The truth of this rule is evident, because any triangle is the half a parallelogram of equal base and... | |
 | William Keane (gardener.) - 1861 - 252 pages
...triangular field whosebase is 6 chains 50 links, and perpendicular height 5 chains 60 links. Rule : — Multiply the base by the perpendicular height and half the product will be the area ; or multiply the one of these divisions by half the other. 6-50 6,50 5-80 2-80 G 39000 32500 \ 52000... | |
 | Janes Boddely Keene - 1861 - 104 pages
...side is 3 yards, and height 3ft. 6in. » Ans. 31ft. 6 parts. Tofind the Area of a Triangle. BCLE. — Multiply the base by the perpendicular height, and half the product will be the area. NOTE. — By adding a similar and equal triangle to the one to be measured, a parallelogram is obtained,... | |
 | Oliver Byrne - Engineering - 1863 - 600 pages
...10-52 x 7-63 = 80-2676 ; 80-2676 and — T7i— = 8-02676 acres = 8 ac. 10 0 ro. 4po. area required. To find the area of a triangle. — Multiply the base...perpendicular height, and half the product will be the area. The perpendicular height of the triangle is equal to twice the area divided by the base. Required the... | |
 | A. C. Smeaton - Building - 1867 - 314 pages
...what is its area ? 17 X 15 =255, the area required. PROBLEM IV. To find the Area of a Triangle. RULE. Multiply the base by the perpendicular height, and half the product will be the area. Let the base of a triangle be 14 feet, and the perpendicular height 9, then 14 X 9 = 126 -=-2 = 63... | |
 | Michael Reynolds - 1877 - 300 pages
...feet 6 inches long and 3 feet 6 inches wide. By Decimals. 5-5 3-5 275 165 19-25 Ans. 19J square feet. To find the area of a triangle, multiply the base by the perpendicular height, and half the product is the area. Required the area of a triangle, of which the base is 15-4 inches, and the perpendicular... | |
 | Daniel Kinnear Clark - Engineering - 1878 - 1022 pages
...breadth. Or, multiply the product of two contiguous sides by the natural sine of the included angle. To find the area of a triangle. Multiply the base by the perpendicular height, and take half the product. Or, multiply half the product of two contiguous sides by the natural sine of... | |
 | Edwin Pliny Seaver - Arithmetic - 1878 - 364 pages
...equal triangles may be placed, as shown in Fig. 15, so as to make a parallelogram. Hence the Rule. To find the area of a triangle : Multiply the base by the height, and divide the product by 2. To find the area of a triangle when the three sides are given... | |
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To find the Area of a Triangle. /.'•'/..• ]. Multiply the base by the perpendicular height, and half the product will be the area. 
