 | Robert Potts - 1865 - 528 pages
...produced to D, so that CD = AC, and BD be joined, Bif = AB* 1 4B C'. V. 43. Prove that the square on any straight line drawn from the vertex of an isosceles triangle to the base, is less than the square on a side of the triangle, by the rectangle contained by the segments... | |
 | Euclid, Isaac Todhunter - Euclid's Elements - 1867 - 426 pages
...and the side AD produced at E: shew that the rectangle EF, FG is equal to the square on BF. 404. If a straight line drawn from the vertex of an isosceles triangle to the base, be produced to meet the circumference of a circle described about the triangle, the rectangle... | |
 | Euclid, Isaac Todhunter - Euclid's Elements - 1867 - 424 pages
...and the side AD produced at E: shew that the rectangle EF, FG is equal to the square on BF. 404. If a straight line drawn from the vertex of an isosceles triangle to the base, be produced to meet the circumference of a circle described about the triangle, the rectangle... | |
 | Robert Potts - 1868 - 434 pages
...is equivalent to twice the rectangle under the extreme segments. V. 37. Prove that the square on any straight line drawn from the vertex of an isosceles triangle to the base, is less than the square on a side of the triangle by the rectangle contained by the segments... | |
 | Adrien Marie Legendre - Geometry - 1871 - 490 pages
...BAD is equal to DAC, and BDA to CDA : hence, the last two are right angles. Consequently, a stra1ght line drawn from the vertex of an isosceles triangle to the middle of the lase, lisects the angle at the vertex, and is perpendicular to the base. PROPOSITION XII. THEOREM.... | |
 | Charles Davies - Geometry - 1872 - 464 pages
...BAD is equal to DAC, and BDA to CDA : hence, the last two are right angles. Consequently, a stra1ght line drawn from the vertex of an isosceles triangle to the middle of t?1e base, bisects the angle at the vertex, and is perpendicular to the base. PROPOSITION XII. THEOREM.... | |
 | Adrien Marie Legendre - Geometry - 1874 - 500 pages
...BAD is equal to DAC, and BDA to CD A : hence, the last two are right angles. Consequently, a stra1ght line drawn from the vertex of an isosceles triangle to the middle of the base, bisects the angle at the vertex, and is perpendicular to the base. PROPOSITION XII. THEOREM. If two... | |
 | Euclides - 1874 - 120 pages
...that the square on the base BC shall be equal to twice the rectangle AC, CD. 74. The square on any straight line drawn from the vertex of an isosceles triangle to the base is less than the square on a side of the triangle by the rectangle contained by the segments of... | |
 | William Guy Peck - Conic sections - 1876 - 376 pages
...equal in all their parts, (P. 11). Hence, the angle A is equal to C, which was to be proved. Cor. 2. A line drawn from the vertex of an isosceles triangle to the middle of the base bisects the angle at the vertex, and is perpendicular to the base. For, from what has just been proved,... | |
 | William Guy Peck - Conic sections - 1876 - 412 pages
...their parts, ( P. 11 ). Hence, the angle A is equal to C, which was to be proved. BOOX 1. Cor. 2. A line drawn from the vertex of an isosceles triangle to the middle of the bose bisects the angle at the vertex, and is perpendicular to the base. For, from what has just been... | |
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Hence a straight line drawn from the vertex of an isosceles triangle, to the middle of the base, is perpendicular to that base, and divides the vertical angle into two equal parts. 
