...triangle the product of two sides is equal to the square of the bisector of their included angle, plus the product of the segments of the third side formed by the Abisector. Given : A ABC, CO bisector of Z ACS. To Prove : a • b = t* + n • r. Proof : Circumscribe...

...drawn from C is 11. Find side BC. (§ 314. ) PLANE GEOMETRY — BOOK III PROPOSITION XXV. THEOREM 318. In any triangle, the product of any two sides is equal...the opposite angle, plus the square of the bisector. • tA. Give full proof. Hypothesis. AD bisects ZA of A ABC, meeting BC at D. (Let BD = r, and DO =...

...BCD. Ex. 51. From the conclusion of § 311, derive a formula for p* in terms of a, 6, and c. Ex. 52. In any triangle, the product of any two sides is equal...segments of the third side formed by the bisector of the exterior angle at the opposite vertex, minus the square of the bisector. D ,- ,. Prove AB x AC = DB...

...SUGGESTION. — To prove AC x BC= CD x CE. Draw BE. 42. In any triangle the product of two sides equals the product of the segments of the third side formed...the opposite angle, plus the square of the bisector. SUGGESTION. — To prove AC x BC = ADx DB+ CD*. Circumscribe a circle about A ABC, extend CD to meet...