 | Benjamin Greenleaf - Arithmetic - 1858 - 332 pages
...represent? What is the rule for extracting the cube root ? Subtract the subtrahend from the dicidend, and to the remainder bring down the next period for a new dicidend, with which proceed at before; and so on, till the whole is completed. NOTE 1. — In separating... | |
 | Benjamin Greenleaf - Arithmetic - 1859 - 334 pages
...its contents ? What part of Fig. 4 does it represent ? What is the rule for extracting the cube root? Subtract the subtrahend from the dividend, and to...next period for a new dividend, with which proceed ai before ; and so on, till the whole is completed. NOTE 1. — In separating the given number into... | |
 | Charles Guilford Burnham - 1859 - 338 pages
...the last ; under these write the cube of the last quotient figure, and call their sum the subtrahend. Subtract the subtrahend from the dividend, and to...remainder bring down the next period, for a new dividend, and proceed as before, till the work is finished. EXAMPLES. 2. What is the cube root of 1906624 ? ,... | |
 | Horatio Nelson Robinson - Arithmetic - 1859 - 352 pages
...the complete divisor. V. Multiply the complete divisor by the trial figure, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. VI. Add the square of the last figure of the root, the last term in column II, and the complete divisor... | |
 | Benjamin Greenleaf - Arithmetic - 1860 - 324 pages
...call their sum the subtrahend. Subtract the subtrahend from the dividend, and to the remainder faing down the next period for a new dividend, with which proceed as before; and so on, till the whole is completed. NOTE 1. — In separating the given number into periods, when the num ber of the figures... | |
 | Horatio Nelson Robinson - Arithmetic - 1860 - 444 pages
...the complete divisor. V. Multiply the complete divisor by the trial figure ; subtract the. product from the dividend, and to the remainder bring down the next period for a new dividend. VI. Add the square of the last figure of the root, the last term in column II, and the complete divisor... | |
 | James Bates Thomson - Arithmetic - 1860 - 440 pages
...; multiply- the divisor thus completed by the figure last placed in the root ; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. IV. Double the root already found for a new partial divisor, divide, <£c., as before, and thus continue... | |
 | Benjamin Greenleaf - Arithmetic - 1860 - 456 pages
...the true divisor, which multiply by the last root figure and subtract the product from the dividend. To the remainder bring down the next period for a new dividend. Double the root already found for a new trial divisor, and continue the operation as before, till all... | |
 | Daniel Adams - Arithmetic - 1861 - 452 pages
...the root (the breadth of the additions), and subtract the contents of the additions thus obtained, from the dividend, and to the remainder bring down the next period for a new dividend. IV. Double the root already found for a new divisor, and continue the operation as before, until all... | |
 | Charles Davies - Algebra - 1861 - 322 pages
...divisor. IV. Multiply the divisor, thus augmented, by the lastfyurt of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. But if any of the products should be greater than the dividend, diminish the last figure of the root... | |
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Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 
