 | Thomas Conkling (W.) - Arithmetic - 1831 - 302 pages
...the number of terms are given, to find the sum of all the terms, Rule. Multiply the sum of the two extremes, by the number of terms, and half the product will be the answer. Or, multiply the sum of the two extremes by half the number of terms. * In any series of numbers,... | |
 | Roswell Chamberlain Smith - Arithmetic - 1831 - 286 pages
...Hence, when the extremes, and the number of terms are given, to find the sum of all the terms ; — Multiply £ the sum of the extremes by the number of terms, and the product will be the answer. 10. If the extremes be 3 and 373, and the number of terms 40, what... | |
 | Francis Walkingame - 1833 - 204 pages
...— 1), and i=^nz. Case 1. The I wo extremes, and the number of terms being given, loßnd ihe sum. RULE. Multiply the sum of the extremes by the number of terms, and half the product will be the answer.* (1) How many strokes does the hammer of a clock strike in 12 hours ft (2) A man bought 17... | |
 | Daniel Adams - Arithmetic - 1833 - 268 pages
...) Hence, when the extremes and the member of terms are given, to find the sum of all the terms, — Multiply £ the sum of the extremes by the number of terms, and the product will be the answer. 10. If the extremes be 5 and 6OS, ?nd the number of terms 151, what... | |
 | Catharine Esther Beecher - Arithmetic - 1833 - 296 pages
...the following rule ; When the extremes and number of terms are given, to find the sum of the terms, Multiply the sum of the extremes by the number of terms, and divide the product by 2. 2. The first term of a series is 1, the last term 29, and the number of terms... | |
 | Frederick Emerson - Arithmetic - 1834 - 300 pages
...The sum of all the terms. PROBLEM. I. The extremes and number of terms being given, to find the sum of all the terms. RULE. Multiply the sum of the extremes by the number of the terms, and half the product will be the sum of all the terms. See Theorem 4th. 1. The first term... | |
 | Stephen Pike - Arithmetic - 1835 - 210 pages
...difference, and to the product add the first ,erm, the sum is fhe. last term. 2. Multiply the sum of the two extremes by the number of terms, and half the product will be the sum of all the terms. EXAHPLES. 1. The first term of a certain series in arithmetical progression is 2, the... | |
 | Nathan Daboll - Arithmetic - 1837 - 262 pages
...of a variety of Problems } but most of them are best understood by an ces», and are her« omitted. RULE. Multiply the sum of the extremes by the number of terms, and half the product will be the answer. EXAMPLES. 1. The first term of an arithmetical series is 3, the last term 23, and the number... | |
 | Luther Ainsworth - Arithmetic - 1837 - 298 pages
...series. Q. What is the RULE in this case ? A. Add the two extremes together, and multiply their sum by the number of terms, and half the product will be the an. swer, or sum of the scries. EXAMPLES. 1. The first term of an arithmetical series is 3, the last... | |
 | James Thomson (LL.D.) - Arithmetic - 1837 - 296 pages
...Answ. 243J. RULE II. The extremes and the number of terms being given, to find the sum of the series .- Multiply the sum of the extremes by the number of terms, and take half the product. Exam. 2. The first term of an equidifferent series is I , its last term 312,... | |
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... terms, RULE. Multiply the sum of the extremes by the number of terms, and half the product will be the sum of the terms. EXAMPLES FOR PRACTICE. 2. If the extremes be 5 and 605, and the number of terms 151, what is the sum of the series? 
