 | Jacob William Albert Young, Lambert Lincoln Jackson - Geometry, Plane - 1916 - 328 pages
...ABC=$hb, Why? and A ACD = \ hb'. Why ? 3. .-. trapezoid ABCD = A ACD + A ABC = QED 365. COROLLARY. The area of a trapezoid is equal to the product of its altitude by the line joining the mid-points of the nonparallel sides. According to Sec. 166, the line joining... | |
 | John Charles Stone, James Franklin Millis - Geometry - 1916 - 306 pages
...Suggestion. Draw DB. Prove that A ABD = l ab and A DCB = \ ac. Then add and factor. 226. Corollary. — The area of a trapezoid is equal to the product of its altitude and the line-segment joining the middle points of its non-parallel sides. See § 98. 227. Area of any... | |
 | William Betz - Geometry - 1916 - 536 pages
...= $bh, §333 and area AADC = ^ b'h. 4. .'. area trapezoid ABCD = \ h(b + b'). Ax. 2 336. COROLLARY. The area of a trapezoid is equal to the product of its altitude and mid-line. § 219 EXERCISES 1. From § 321 derive a proof for the above theorem by means of the... | |
 | William Betz, Harrison Emmett Webb - Geometry, Solid - 1916 - 214 pages
...The area of a trapezoid is equal to half the product of its altitude and the sum of its bases. 336. The area of a trapezoid is equal to the product of its altitude and mid-line. 337. If two triangles have an angle of one equal to an angle of the other, their areas... | |
 | Fletcher Durell, Elmer Ellsworth Arnold - Geometry, Plane - 1917 - 330 pages
...to 12' 10 ' 20 20 1/6" __^ 13' W 25' 40' 28' (2) CJ) AREAS OF POLYGONS PROPOSITION VII. THEOREM 350. The area of a trapezoid is equal to the product of its altitude and half the sum of its parallel sides. Given the trapezoid AB CD with the bases AD and BC (denoted... | |
 | Herbert Ellsworth Slaught - 1918 - 344 pages
...area A ACD = $bh + % b'h. § 411 .-. Area ABCD = i bh + i b'h = \ h(b + b'). °- B- D418. COROLLARY. The area of a trapezoid is equal to the product of its altitude and its median. Suggestion. Use § 187. EXPERIMENTAL GEOMETRY 1. In the figure, the two triangles are... | |
 | Herbert Ellsworth Slaught, Nels Johann Lennes - Geometry, Plane - 1918 - 360 pages
...$bh + ± b'h. § 411 .-. Area ABCD = %bh + J- b'h = \h(b + b'). Q- «• »• 418. COROLLARY. Tlie area of a trapezoid is equal to the product of its altitude and its median. Suggestion. Use § ]87. EXPERIMENTAL GEOMETRY 1. In the figure, the two triangles are... | |
 | Charles Austin Hobbs - Geometry, Solid - 1921 - 216 pages
...Prop. 151, Cor. III. Two triangles having equal bases are to each other as their altitudes. Prop. 152. The area of a trapezoid is equal to the product of its altitude and one half the sum of its bases. Prop. 153. Two triangles haring an angle of one equal to an angle... | |
 | Raleigh Schorling, William David Reeve - Mathematics - 1922 - 476 pages
...T) B. Then prove that the area of AABD= ^ and that of AZ>SC= J bh. Add and factor. 457. Corollary. The area of a trapezoid is equal to the product of its altitude and the line segment which joins the midpoints of its nonparallel sides. EXERCISES 1. Find the area... | |
 | College Entrance Examination Board - Mathematics - 1920 - 108 pages
...Geometry, is printed on page 1.] 1. Prove: The diagonals of a parallelogram bisect each other. 2. Prove: The area of a trapezoid is equal to the product of its altitude and half the sum of its parallel sides. 3. Prove: The bisector of an angle of a triangle divides the... | |
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Theorem. — The area of a trapezoid is equal to the product of its altitude... 
