| Thomas Tate (Mathematical Master, Training College, Battersea.) - 1860 - 404 pages
...right angles . 12 COR. The sum of the interior angles of any convex polygon together with four right angles is equal to twice as many right angles as the polygon has sides 12 CONGRUENT TRIANGLES. Note on the method of superposition 13 THEOREM 10. If two triangles have two... | |
| 464 pages
...right angles 266 COR. The sum of the interior angles of any convex polygon together with four right angles is equal to twice as many right angles as the polygon has sides 266 CONGRUENT TRIANGLEs. THEOREM 10. If two triangles have two sides of the one equal to two sides... | |
| James McMahon - 2018 - 244 pages
...right angles 83 COR. The sum of the interior angles of any convex polygon together with four right angles is equal to twice as many right angles as the polygon has sides 83 CONGRUENT TRIANGLES 85 Method of superposition ....... 85 THEOREM 10. If two triangles have two... | |
| 480 pages
...Th. 1, Cor. QED COR. The sum of the interior angles of any convex polygon together with four right angles is equal to twice as many right angles as the polygon has sides. [For the interior and exterior angles at n vertices = nx 2 rt. L s, .'. the interior angles = (2ra... | |
| Sir Norman Lockyer - Electronic journals - 1901 - 688 pages
...(Grynaeus-Bale, 1533 AD) these two corollaries are given : — (1) The sum of the interior angles of any polygon is equal to twice as many right angles as the polygon has sides less two. (2) The sum of the exterior angles of any polygon is equal to four right angles. STAM. EUMORKOPOULOS.... | |
| 562 pages
...sides ; [i. 32] therefore the interior angles of the polygon together with all the angles round O are equal to twice as many right angles as the polygon has sides. Also the sum of the angles of the triangles VAB, VBC, etc., with vertex Fare equal to twice as many... | |
| 1903 - 886 pages
...540°.) FIG. I8.-PROPOSITIONS RELATING TO POLYGONS Prop. XV. — The sum of all the angles of any polygon is equal to twice as many right angles as the polygon has angles, less 4 right angles. (In Fig. 19 we find by the use of a protractor that the sum of the angles... | |
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