 | Benjamin Greenleaf - Arithmetic - 1857 - 336 pages
...figure last annexed by the figure annexed to the root, and subtract the product from the dividend. To the remainder bring down the next period for a new dividend. Double the root already found for a new divisor, and continue the operation as before, till all the... | |
 | Joseph Ray - Arithmetic - 1857 - 348 pages
...Multiply the complete dicisor by the last figure of the root, and subtract the product from the dividend; to the remainder bring down the next period for a new dividend, and so proceed until all the periods are brought down. NOTES. — 1. When the product of the complete... | |
 | Thomas William Silloway - Carpentry - 1858 - 236 pages
...likewise on the right hand of the divisor. Multiply the divisor by the last quotient-figure, subtract the product from the dividend, and to the remainder bring down the next period for a new dividend, 4th, Double the quotient already found for a partial divisor, and from these find the next figure in... | |
 | Benjamin Greenleaf - Arithmetic - 1858 - 472 pages
...last figure, for a true divisor. Multiply the true divisor by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. Multiply the square of (lie root figures already found by 3, and to the product annex two ciphers for... | |
 | Elias Loomis - Algebra - 1858 - 394 pages
...the second figure. 5. Multiply the divisor thus increased by the last figure of the root ; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 6. Take three hundred times the square of the whole root now found for a new trial divisor, and continue... | |
 | Benjamin Greenleaf - Arithmetic - 1858 - 458 pages
...to the same for a true divisor. Multiply the true divisor by the last figure of the root : subtract the product from the dividend, and to the remainder bring down the next period far a new dividend. To the last true divisor and the number immediately over it, add the square of... | |
 | Charles Haynes Haswell - Measurement - 1858 - 350 pages
...period, and place its root in the quotient ; subtract the square number from the left-hand period, and to the remainder bring down the 'next period for a new dividend. Double the root already found for a divisor ; find how many times this incomplete divisor is contained... | |
 | Benjamin Greenleaf - Arithmetic - 1858 - 332 pages
...represent? What is the rule for extracting the cube root ? Subtract the subtrahend from the dicidend, and to the remainder bring down the next period for a new dicidend, with which proceed at before; and so on, till the whole is completed. NOTE 1. — In separating... | |
 | Benjamin Greenleaf - Arithmetic - 1859 - 334 pages
...of Fig. 4 does it represent ? What is the rule for extracting the cube root? Subtract the subtrahend from the dividend, and to the remainder bring down...next period for a new dividend, with which proceed ai before ; and so on, till the whole is completed. NOTE 1. — In separating the given number into... | |
 | Horatio Nelson Robinson - Arithmetic - 1859 - 348 pages
...result will be the complete divisor. V. Multiply the complete divisor by the trial figure, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. VI. AdAt the square of the last figure of the root, the last term in column II, and the complete divisor... | |
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Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 
