 | Charles Guilford Burnham - Arithmetic - 1857 - 328 pages
...of the interest for 1 year, is to the given interest, as 1 year is to the time required. Hence the RULE. Divide the given interest by the interest of the given principal for 1 year, and the quotient will be the answer. 2. In what time will $240 gain $4.80, at 6 per cent. ? Ans. 4 months. 3. In what... | |
 | Benjamin Greenleaf - Arithmetic - 1857 - 336 pages
...1 per cent., $48 will be as many per cent, as $6 is contained times in $48, which gives 8 per cent, for the answer. RULE. — Divide the given interest by the interest of the given sum at 1 per cent, for the given time, and the quotient will be the rale per cent, required. QUESTIONS... | |
 | Benjamin Greenleaf - Arithmetic - 1857 - 452 pages
...; then the required rate will be as many per cent. as 20 is contained times in 120, or 6 per cent. RULE. — Divide the given interest by the interest of the given principal at 1 per cent. for the given time. EXAMPLES. 2. The interest of $ 144 for 1 year is $ 10.08 ; what... | |
 | Benjamin Greenleaf - Arithmetic - 1858 - 472 pages
...produce $ 1 20 interest there will be required as many years as 30 is contained times in 120, or 4 years. RULE. — Divide the given interest by the interest of the given principal for 1 year. EXAMPLES. 2. How long must $ 120 be on interest, at 8£ per cent., to gain $ 13.20 ? Ans. lyr. 4mo.... | |
 | Benjamin Greenleaf - Arithmetic - 1858 - 458 pages
...cent. ; then the required rate will be as many per cent, as 20 is contained times in 120, or 6 per cent RULE. — Divide the given interest by the interest of the given principal at 1 per cent, for the given time. EXAMPLES. 2. The interest of $ 144 for 1 year is $ 10.08 ; what... | |
 | Charles Guilford Burnham - 1859 - 338 pages
...of the interest for 1 year, is to the given interest, as 1 year is to the time required. Hence the RULE. Divide the given interest by the interest of the given principal Jar 1 year, and the quotient will be the answer. 2. In what time will $240 gain $4.80, at 6 per cent.... | |
 | Benjamin Greenleaf - Arithmetic - 1860 - 324 pages
...contained times iu $36, which gives 2 years for the answer. RULE. — Divide the given interest ly the interest of the given principal for 1 year, and the quotient will be the time. EXAMPLES FOR PRACTICE. 2. If the interest of $140 at 6 per cent, is $42, for how... | |
 | Benjamin Greenleaf - Arithmetic - 1860 - 456 pages
...there will be required as many years as 30 is contained times in 120, or 4 years. RULE. — Divide (he given interest by the interest of the given principal for 1 year. * u EXAMPLES. 2. How long must $ 120 be on interest, at 8£ per cent., to gain $ 13.20 ? Ans. lyr.... | |
 | Benjamin Greenleaf - Arithmetic - 1861 - 338 pages
...to gain $18, it will require as many years to gain $36 as $18 is contained times iu $36, which gives 2 years for the answer. RULE. — Divide the given...of the given principal for 1 year, and the quotient will be the time. EXAMPLES FOR PRACTICE. 2. If the interest of $140 at 6 per cent. is $42, for how... | |
 | George Roberts Perkins - Arithmetic - 1865 - 360 pages
...than the interest for ono year, as the particular time is greater than 1 year. Hence, we have this RULE. Divide the given interest by the interest of the given principal, for 1 year, at the given rate per cent. EXAMPLES. 1. In what time will $37-13. at 4i per cent., give 80-75 18825... | |
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RULE. — Divide the given interest by the interest of the given principal for 1 year, and the quotient is the time. 
