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" RULE. — Divide the given interest by the interest of the given principal for 1 year, and the quotient is the time. "
Indroduction to the National Arithmetic ... - Page 211
by Benjamin Greenleaf - 1854
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The Complete Arithmetic, Oral and Written: Second Part

Daniel W. Fish - Arithmetic - 1876 - 302 pages
...6 mo. 18 da, In what time 2. Will $175.12 gain $6.43 at 6$? 3. Will $1000 amount to $1500 at 7£$? RULE. — Divide the given interest by the interest of the given principal, at the given rate for 1 year. FORMULA. — Time = Interest ~ (Prin. x Rate). 4. In what time will $8750...
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The Complete Arithmetic

Milton Browning Goff - Arithmetic - 1876 - 462 pages
...contained times in $28.875, or 3 times. Therefore, at 1% , $137.50 will gain $28.875 in 3 yr. 361. RULE. — Divide the given interest by the interest of the given principal at the given rate for one year ; the quotient is the time in years. I j, = t.\ \7" x -DI 22 PROBLEMS....
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The Complete Arithmetic: Combining Oral and Written Exercises in a Natural ...

Albert Newton Raub - Arithmetic - 1877 - 348 pages
...contained times in $138.60, or 6%. From the foregoing we derive the rule to find the rate per cent. : RULE. Divide the given interest by the interest of the given principal for the given time, at 1 per cent. 2. The interest on $1255 for 6 yr. 3 mo. is $313.75 : what is the rate...
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The New American Arithmetic, Part 3

Samuel Mecutchen, George Mornton Sayre - Arithmetic - 1877 - 200 pages
...will take as many % as 5.11^- is contained times in 30.66§-, which = 6. The rate, therefore, is 6 % . RULE. Divide the given interest by the interest of the given principal for the given time at one per cent. %. At what rate will $180 yield $27 interest in 3 years? 3. At what...
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The New American Arithmetic, Part 3

Samuel Mecutchen, George Mornton Sayre - Arithmetic - 1877 - 200 pages
...same rate will take as many years as $30 is contained times in $45, which = 1^. 1^ years = 1 yr. 6 mo. RULE. Divide the given interest by the interest of the given principal at the given rate for one year. 2. I lent a friend $1300, at Q%; at settlement he owed me $1339; how...
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The National Arithmetic on the Inductive System: Combining the Analytic and ...

Benjamin Greenleaf - Arithmetic - 1878 - 468 pages
...; then the required rate will be as many per cent, as 20 is contained times in 120, or 6 per cent. RULE. — Divide the given interest by the interest of the given principal at 1 per cent, for the given time. EXAMPLES. y 2. The interest of $ 144 for 1 year is $ 10.08 ; what...
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The Indiana School Journal, Volume 25

Education - 1880 - 956 pages
...instead of "fer cent." f And why did he find the interest on one dollar? He then says, "according to the rule, divide the given interest by the interest of the given principal for the given time at one per cent.", and divides 100 by 16% and says il= 6 per cent. Now it seems to me...
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Graded Problems in Arithmetic and Mensuration

Samuel Mecutchen - Arithmetic - 1880 - 262 pages
...rate ; or, divide the given amount by the amount of one dollar for the given time and rate. CASE III. Divide the given interest by the interest of the given principal for the given time at one -per cent. CASE IV. Divide the given interest by the interest of the given principal...
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Graded Problems in Arithmetic and Mensuration

Samuel Mecutchen - Arithmetic - 1880 - 270 pages
...rate ; or, divide the given amount by the amount of one dollar for the given time and rate. CASE III. Divide the given interest by the interest of the given principal for the given time at one per cent. CASE IV. Divide the given interest by the interest of the given principal...
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The Packard Commercial Arithmetic

Silas Sadler Packard, Byron Horton - Business mathematics - 1882 - 224 pages
...as $25.56 is contained times in $59.427, or 2.325 yr. 2.325 yr. equal 2 yr. 3 mo. 27 da. (201). 323. RULE. — Divide the given interest by the interest of the given principal, at the given rate, for 1 year. The integral part of the quotient will be years. Reduce the decimal,...
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